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nevsk [136]
2 years ago
5

A satellite orbiting Mars (6.39x1023kg) experiences a gravitational field of 2.40N/kg. How far from Mars is the satellite orbiti

ng?
Physics
1 answer:
Ann [662]2 years ago
4 0

Answer:

sorry dont know

Explanation:

You might be interested in
when a metal ball is heated through 30°c,it volume becomes 1.0018cm^3 if the linear expansivity of the material of the ball is 2
Vlad1618 [11]

Answer:

The original volume of the metal sphere is approximately 1 cm³

Explanation:

The given parameters are;

The temperature change of the metal ball, ΔT = 30°C = 30 K

The new volume of the metal ball, V₂  = 1.0018 cm³

The linear expansivity of the material ball, α = 2.0 × 10⁻⁵ K⁻¹

We have;

d₂ = d₁·(1 + α·ΔT)

Where;

d₁ = The original diameter of the metal ball

d₂ = The new diameter of the ball

From the volume of the ball, V₂, we have;

V₂ = 1.0018 cm³ = (4/3)×π×r₂³

Where;

r₂ = The new radius = d₂/2

∴ V₂ = 1.0018 cm³ = (4/3)×π×(d₂/2)³

∴ d₂ = ∛(2³ × 1.0018 cm³/((4/3) × π)) ≈ 1.241445 cm

d₁ = d₂/(1 + α·ΔT)

∴ d₁ ≈ 1.241445 cm/(1 + 2.0 × 10⁻⁵·K × 30 K) ≈ 1.24070058 cm

The original volume of the metal ball, V₁ = (4/3)×π×(d₁/2)³

∴ V₁ = (4/3)×π×(1.24070058/2)³ ≈ 0.99999902845 cm³ ≈ 1 cm³

The original volume of the metal sphere, V₁ ≈ 1 cm³.

8 0
2 years ago
Why do stars twinkle​
vlada-n [284]

As light from a star races through our atmosphere, it bounces and bumps through the different layers, bending the light before you see it. Since the hot and cold layers of air keep moving, the bending of the light changes too, which causes the star's appearance to wobble or twinkle.

4 0
2 years ago
A volume variance is the difference between overhead at maximum production volume and that at the budgeted production volume.
umka21 [38]
The statement is not correct. Therefore, the answer is letter B. False. The actual definition of a volume variance is that it is the difference of the quantity consumed and the amount budgeted to be sold, the difference will furthermore be multiplied to the standard unit per price. 
3 0
3 years ago
One end of a steel rod of radius R = 10 mm and length L = 80cm is held in a vise. A force of magnitude F = 60kN is then applied
Alexandra [31]

Answer: 1.91*10^8 N/m²

Explanation:

Given

Radius of the steel, R = 10 mm = 0.01 m

Length of the steel, L = 80 cm = 0.8 m

Force applied on the steel, F = 60 kN

Stress on the rod, = ?

Area of the rod, A = πr²

A = 3.142 * 0.01²

A = 0.0003142

Stress = Force applied on the steel/Area of the steel

Stress = F/A

Stress = 60*10^3 / 0.0003142

Stress = 1.91*10^8 N/m²

From the calculations above, we can therefore say, the stress on the rod is 1.91*10^8 N/m²

8 0
3 years ago
What is the concentration of H+ ions at a pH = 7? mol/L What is the concentration of OH– ions at a pH = 7? mol/L What is the rat
AnnZ [28]
<h3><u>Answer;</u></h3>

= 0.0000001 mol/L  

= 0.0000001 mol/L  

= 1:1

<h3><u>Explanation;</u></h3>

What is the concentration of H+ ions at a pH = 7?

The formula for ph is given by:

pH=−log10[H+]

In calculating for the concentration of hydrogen ion, the formula is given by:

[H+]=(10)^(-pH)

Therefore; at pH = 7

[H+]=(10)^(-7)

<u>= 0.0000001 mol/L </u> 

What is the concentration of OH– ions at a pH = 7?

pH+pOH=14

7+pOH=14

pOH= 7

[OH-]=(10)^(-pOH)

[OH-]=(10)^(-7)

<u>= 0.0000001 mol/L  </u>

What is the ratio of H+ ions to OH– ions at a pH = 7?  

1:1

8 0
3 years ago
Read 2 more answers
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