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Genrish500 [490]
3 years ago
10

Calculate the pressure exerted on the floor by the boy standing on both feet if the weight of the boy is 40kg. Assume that the a

rea of each of his shoes is 6cm x 25cm.
(Take 1kg of weight = 10N)
Physics
1 answer:
Jlenok [28]3 years ago
4 0

Answer:

P = 1333.33 N

Explanation:

The pressure exerted by the boy on the floor can be calculated by the following equation:

P = \frac{F}{A}

where,

P = Pressure exerted by the boy = ?

F = Force Applied = Weight of Boy = 40 kg = 40 N (since 1 kg = 1N)

A = Area of application of force = 2(Area of one show) = 2(6 cm x 25 cm)

A = 2(0.06 m x 0.25 m) = 0.03 m²

Therefore,

P = \frac{40\ N}{0.03\ m^2}\\\\

<u>P = 1333.33 N</u>

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A truck is carrying a refrigerator as shown in the figure. The height of the refrigerator is 158.0 cm, the width is 60.0 cm. The
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The maximum acceleration the truck can have so that the refrigerator does not tip over is 1.86m/s².

<h3>What is acceleration?</h3>

Acceleration is the change in velocity with time.

The maximum acceleration is obtained by taking moments about the tipping point of rotation.

  • Moment = force * perpendicular distance
  • Clockwise moment = Anticlockwise moment

F₂ * 1.58 m = F₁ * 0.67 m

where

F₂ is tipping force = mass * acceleration, a

F₁ is weight = mass * acceleration due to gravity, g

The weight acts at a distance half the width of the refrigerator = 30 cm or 0.3 m

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m * a * 1.58 = m * 9.81 * 0.30

a = 1.86 m/s²

The maximum acceleration the truck can have so that the refrigerator does not tip over is 1.86m/s².

In conclusion, if the maximum acceleration is exceeded, the refrigerator will tip over.

Learn more about acceleration at: brainly.com/question/14344386

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8 0
2 years ago
A police car parked on the side of the highway emits a 1200 Hz sound that bounces off a vehicle farther down the highway and ret
emmasim [6.3K]

f' = frequency observed by the police car after sound reflected from the vehicle and comes back to police car = 1250 Hz

f = frequency emitted by the police car  = 1200 Hz

V = speed of sound = 340 m/s

v = speed of vehicle = ?

frequency observed by the police car is given as

f' = f (V + v)/(V - v)

inserting the values in the above equation

1250 = 1200 (340 + v)/(340 - v)

v = 6.9 m/s

4 0
4 years ago
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A person on a sled coasts down a hill and then goes over a slight rise with speed 2.7 m/s. The top of the rise can be modeled as
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3 years ago
Poorly treated municipal wastewater is discharged to a stream. The river flow rate upstream of the discharge point is Qu/s = 8.7
Musya8 [376]

Answer

given,

Q u  = 8.7 m³/s

Q d= 0.9 m³/s

BOD concentration = 50 mg/L

a) BOD concentration at the down stream

C_{down}=\dfrac{0.9\times 50}{8.7+0.9}

C_{down}=\dfrac{0.9\times 50}{9.6}

               = 4.69 mg/L

b) discharge = 9.6 m³/s

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velocity steam = \dfrac{8.7+0.9}{10}

                        = 0.96 m/s

time taken to move 50 km down stream =\dfrac{50 \times 1000}{0.96}

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now,

C_t=C_0e^{-kt}

C_t=4.6875\ e^{-0.2\times 0.6}

C_t = 4.16 mg/L

5 0
4 years ago
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