I’m pretty sure you would have to make them equal
1. 3x -10=7x+14
2. Add 10 to both sides
3. 3x=7x+24
4. Subtract the variable ( 7x ) from both sides
5. -4x=24
6. Divide -4/24
I hope I did it right let me know if any errors
Answer:
A: The interquartile range is 8.
Step-by-step explanation:
Hopefully this helps!
Since the signs are different, you have to subtract. 2
Answer:
Option D. (x + 4)(x + 1)
Step-by-step explanation:
From the question given above, the following data were obtained:
C = (6x + 2) L
D = (3x² + 6x + 9) L
Also, we were told that half of container C is full and one third of container D is full. Thus the volume of liquid in each container can be obtained as follow:
Volume in C = ½C
Volume in C = ½(6x + 2)
Volume in C = (3x + 1) L
Volume in D = ⅓D
Volume in D = ⅓(3x² + 6x + 9)
Volume in D = (x² + 2x + 3) L
Finally, we shall determine the total volume of liquid in the two containers. This can be obtained as follow:
Volume in C = (3x + 1) L
Volume in D = (x² + 2x + 3) L
Total volume =?
Total volume = Volume in C + Volume in D
Total volume = (3x + 1) + (x² + 2x + 3)
= 3x + 1 + x² + 2x + 3
= x² + 5x + 4
Factorise
x² + 5x + 4
x² + x + 4x + 4
x(x + 1) + 4(x + 1)
(x + 4)(x + 1)
Thus, the total volume of liquid in the two containers is (x + 4)(x + 1) L.
1.
Answer C.
2.
Answers B. and C.
3.
Answer B.
4.
Answer A.
5.
Answer A.
