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Lemur [1.5K]
3 years ago
15

Which of the following statements does NOT describe the anomeric carbon? A. This carbon is attached to two oxygens. B. This carb

on is chiral. C. The hydroxyl group on this carbon can be above or below the ring. D. It is the carbon of the carbonyl in the open-chain form of the sugar. E. All of the statements describe the anomeric carbon

Chemistry
1 answer:
MaRussiya [10]3 years ago
8 0

Answer:

The answer is E. All of the statements describe the anomeric carbon.

Explanation:

When a sugar switches from its open form to its ring form, the carbon from the carbonyl (aldehyde if it is an aldose, or a ketone in the case of a ketose) suffers a nucleophilic addition by one of the hydroxyls in the chain, preferably one that will form a 5 or 6 membered ring after the reaction.

As such, the anomeric carbon will have two oxygens attached (The original one and the one that bonded when the ring closed).

It will be chiral, given that it has 4 different groups attached. (-OR,-OH,-H and -R, where R is the carbon chain).

The hydroxyl group can be in any position (Above of below the ring), depending on with side the addition took place. (See attachment)

It is the carbon of the carbonyl in the open-chain form of the sugar, because it is the only one that can react with the Hydroxyls.

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3 years ago
30 POINTS PLEASE HELP ME I NEED YALL PLEASE
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2 years ago
Read 2 more answers
A solution of the primary standard potassium hydrogen phthalate (KHP), KHC8H4O4 , was prepared by dissolving 0.4877 g of KHP in
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<u>Answer:</u> The concentration of KOH solution is 0.103 M.

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Given mass of KHP = 0.4877 g

Molar mass of KHP = 204.22 g/mol

Putting values in equation 1, we get:

\text{Moles of KHP}=\frac{0.4877g}{204.22g/mol}=0.0024mol

The chemical reaction for the reaction of KHP with KOH follows:

KHC_8H_4O_4(aq.)+KOH\rightarrow K_2C_8H_4O_4(aq.)+H_2O(l)

By Stoichiometry of the reaction:

1 mole of KHP reacts with 1 mole of KOH.

So, 0.0024 moles of KHP will react with = \frac{1}{1}\times 0.0024=0.0024mol of KOH.

  • To calculate the molarity of KOH, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}

We are given:

Moles of KOH = 0.0024 moles

Volume of solution = 23.22 mL  = 0.02322L      (Conversion factor:  1L = 1000 mL)

Putting values in above equation, we get:

\text{Molarity of KOH }=\frac{0.0024mol}{0.02322L}=0.103M

Hence, the molarity of KOH solution is 0.103 M.

6 0
3 years ago
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