Answer: <span>Based on giveninformation, the compound is a
<u>Poly Unsaturated</u> fatty acid.
Explanation: Fatty acids are carboxylic acids with -COOH functional group and a chain of hydrocarbons.
Fatty Acids are classified as,
i) Saturated Fatty Acids: Those Fatty Acids in which there is no double bond between the carbon chain are called as saturated fatty acids.
Examples: Lauric Acid </span>CH₃(CH₂)₁₀COOH<span>
Myristic Acid </span>CH₃(CH₂)₁₂COOH<span>
Palmitic Acid </span>CH₃(CH₂)₁₄COOH
ii) Unsaturated Fatty Acids: Those Fatty Acids in which contain a single double bond (mono-unsaturated) or more than one double bond (poly-unsaturated) d between the carbon atoms in a chain are called as unsaturated fatty acids.
Examples: <span>
Linoleic acid</span>
<span>
Vaccenic acid </span><span>
Palmitoleic acid
The saturated fatty acid containing 26 carbon atoms is called as
Cerotic acid. While cerotic acid containing a double bond at position 3 and 9 has a IUPAC name
H</span>
exacosa-3,9-dienoic acid with following structure.
The balanced chemical equation will tell you the molar ratios in which hydrogen and oxygen react to form water:
2H2 + O2 ----> 2H2O
Then the ratio is 2 mol of H2 react with 1 mol of O2 and form 2 mol of H2O:
2 : 1 : 2
Now convert the given data into moles:
16 grams of H2 = 16 g / 2 g/mol = 8 mol
16 grams of O2 = 16 g / 16 g/mol = 1 mol.
Then you have that the 1 mol of oxygen will react with 2 moles of hydrogen and they will form 2 mol of H2O.
And you can calculate the mass of 2 moles of H2O by multiplying by its molar weigth: 18 g/mol.
2 mol H2O * 18 g/mol = 36 grams of water.
Then, the answer is 36 grams of H2O.
Answer:Ionic compounds form when positive and negative ions share electrons and form an ionic bond. ... The positive ion, called a cation, is listed first in an ionic compound formula, followed by the negative ion, called an anion. A balanced formula has a neutral electrical charge or net charge of zero.
Explanation:Simple ions:
Perchlorate ClO4- IO3-
Chlorate ClO3- BrO3-
Chlorite ClO2-
Hypochlorite OCl- OBr-
The Molarity of solution that contain 2.3 mole of NaCl in 0.45L of solution is calculated using the below equation
= molarity = moles/volume in liters
= 2.3 moles/0.45 L = 5.1 M