Hey there!
Balance the equation:
SiCl₄ + H₂O → H₄SiO₄ + HCl
Balance H.
2 on the left, 5 on the right. Add a coefficient of 3 in front of H₂O and a coefficient of 2 in front of HCl.
SiCl₄ + 3H₂O → H₄SiO₄ + 2HCl
Balance O.
3 on the left, 4 on the right. Change the coefficient of 3 in front of H₂O to a 4.
SiCl₄ + 4H₂O → H₄SiO₄ + 2HCl
This unbalanced our H, so change the coefficient of 2 in front of HCl to a 4.
SiCl₄ + 4H₂O → H₄SiO₄ + 4HCl
Balance Cl.
4 on the left, 4 on the right. Already balanced.
Balance Si.
1 on the left, 1 on the right. Already balanced.
Our final balanced equation:
SiCl₄ + 4H₂O → H₄SiO₄ + 4HCl
Hope this helps!
Sun⇒ Phytoplankton (Producer)⇒ Zooplankton (Primary consumer)⇒ Fish (Secondary consumer)⇒ Bear (Tertiary consumer).
- A food chain is a sequence of transfer of food and energy when one organism is consumed by another organism.
- A food chain is always unidirectional sequence.
- In the provided food chain the sun is the source of energy required for the preparation of food by the phytoplankton that is an aquatic autotroph which will prepare its food by the process of photosynthesis.
- The phytoplankton being producer of biomass is consumed by the zooplankton that is the primary consumer than the zooplankton will be consumed by the fish that is the secondary consumer and carnivore by origin and finally the fish will be consumed by the bear that is also carnivore and is tertiary consumer.
Learn more about food chain:
brainly.com/question/16543685
Answer:
sediment from melting glaciers being deposited in lakes
Explanation:
I took the test
Answer:
Approximately 
(approximately 
.)
Explanation:
Calculate the quantity 
of lithium phosphate in 
of this
lithium phosphate solution.
.
Empirical formula of lithium phosphate: 
.
Look up the relative atomic mass of 
, 
,and 
on a modern periodic table:
Calculate the formula mass of :
.
Calculate the mass of that 
of formula units:
.
V = 75 mL = 0,075 L = 0,075 dm³
C = 2.1M
n = ?
---------------
C = n/V
n = C×V
n = 2.1×0,075
n = 0,1575 mol
--------
mKCl: 39+35.5 = 74,5 g/mol
74,5g --------- 1 mol
Xg ------------- 0,1575 mol
X = 74,5×0,1575
X = 11,73375g KCl
:•)
.
.
.