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adell [148]
3 years ago
12

Select the correct difference. -3z 5 - (-7z 5) -10z5 -4z5 4z5 4z

Mathematics
2 answers:
bezimeni [28]3 years ago
8 0

-10z5 is the answer.


Alinara [238K]3 years ago
3 0
<span>-10z5 is the answer. </span>
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Find the range of the parent function below y=x^2
marusya05 [52]

you don't show the graph, but graphing y=x^2 it is a U shaped line that starts at (0,0) and the lines go upwards on both sides of the Y axis,

 This means all real numbers above 0 and 0 will solve it

 so the range is y≥0

6 0
3 years ago
Is a rectangle a plane shape​
Triss [41]

Answer:

A plane shape with four straight sides and four right angles for corners is called a rectangle.

Step-by-step explanation:

3 0
2 years ago
2. A soccer field is bordered on three sides by a parking lot of width x. The total
notsponge [240]

Answer: 50m

Step-by-step explanation:

this is the logical way I solved it:

1. Find the area of the entire area thing

300*200=60000

2. Subtract the area of the field from the area of the entire place

60000-30000=30000

3. Divide the area of the parking by three because there are three sides

30000 ÷ 3 = 10000

4. Divide 10000 by 200, not 300 because we want to find the side with one <em>x</em>, not two <em>x</em> (there are two sides adding on to the side with 300, but only one side on the side with 200)

10000÷200= 50

I know the steps are weird, but I know this is the right answer because this was on the unit test (same misspelling and everything lol) and during tutoring my teacher showed me how to do it, but of course I had to forget the steps.

4 0
3 years ago
What is the solution to <br> 5x+9-3x=18+15<br><br> A.x=8<br> B.x=12<br> C.x=21<br> D.x=3
Vlad [161]
Your answer will be B) x=12

1)5x-3x
2) move 9 to the other side (change signs)
3)18+15-9
4) 2x= 24 (divide 2 from both sides
5)x=12

hope this helps
7 0
3 years ago
Read 2 more answers
1-cos^2 A / sec^2 A - tan^2 A
tiny-mole [99]
I hope this helps you



✔cos^2A+sin^2A=1


✔1-cos^2A=sin^2A

✔cos2A=cos^2A-sin^2A

✔sin2A=2.sinA.cosA


secA=1/cosA


tgA=sinA/cosA


sin^2A/1/cos^2A-sin^2A/cos^2A


sin^2A.cos^2A/cos2A

2.sin^2A.cos^2A/cos2A


sin2A.2.sin2A/cos2A


tg2A.2.sin2A


6 0
2 years ago
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