answer:
Simplifying Y2 + -20X + -6y + -51 = 0
Reorder the terms: -51 + -20X + Y2 + -6y = 0
Solving -51 + -20X + Y2 + -6y = 0
Solving for variable 'X'.
Move all terms containing X to the left, all other terms to the right.
Add '51' to each side of the equation. -51 + -20X + Y2 + 51 + -6y = 0 + 51
Reorder the terms: -51 + 51 + -20X + Y2 + -6y = 0 + 51 Combine like terms: -51 + 51 = 0 0 + -20X + Y2 + -6y = 0 + 51 -20X + Y2 + -6y = 0 + 51
Combine like terms: 0 + 51 = 51 -20X + Y2 + -6y = 51
Add '-1Y2' to each side of the equation. -20X + Y2 + -1Y2 + -6y = 51 + -1Y2
Combine like terms: Y2 + -1Y2 = 0 -20X + 0 + -6y = 51 + -1Y2 -20X + -6y = 51 + -1Y2 Add '6y' to each side of the equation. -20X + -6y + 6y = 51 + -1Y2 + 6y Combine like terms: -6y + 6y = 0 -20X + 0 = 51 + -1Y2 + 6y -20X = 51 + -1Y2 + 6y Divide each side by '-20'. X = -2.55 + 0.05Y2 + -0.3y Simplifying X = -2.55 + 0.05Y2 + -0.3y
1st question: ∠G = 180 - (104+33) = 43°. According to the picture, we can claim that. Indeed, we considered that ∠N= ∠H.
2nd question: In order to carry out this transformation, using similarity transformation the following steps must be applied
1) From the center of the second circle to the center of the first circle, a vector has to be drawn
2) The second circle must be carried to the first circle by this vector.
3) Finally, the transformation is done by this dilation. Indeed, everything comes to the theorem for the similarity of the circles that all circles are similar.
And the scale factor is
It just so happens that it's always the same y for each x, but it is only that one y. So this is a function; it's just an extremely boring function! ... So this is a relation, but it is not a function.
1/3, because the probability in the cube is 1/6, and there are 2 numbers less than 3. So, 2/6 and simplify 2/6 to 1/3.