<u><em>Answer:</em></u>
Area of rhombus = 126 m²
<u><em>Explanation:</em></u>
<u>We are given that the two diagonals of the rhombus are:</u>
D₁ = 14 meters and D₂ = 18 meters
<u>The area of the rhombus using its diagonals can be calculated using the following rule:</u>
<u>Substitute with the given values to get the area as follows:</u>
Hope this helps :)
Step-by-step explanation:
Answer:
The answer is B. 12 cm
Step-by-step explanation:
ABC is a right triangle
AB and BC are the legs and AC is the hypotenuse.
The Pythagorean theorem a^2 + b^2 = c^2 can be manipulated to solve for a and get 12.
Step-by-step explanation:
Use the quadratic formula
=
−
±
2
−
4
√
2
x=\frac{-{\color{#e8710a}{b}} \pm \sqrt{{\color{#e8710a}{b}}^{2}-4{\color{#c92786}{a}}{\color{#129eaf}{c}}}}{2{\color{#c92786}{a}}}
x=2a−b±b2−4ac
Once in standard form, identify a, b and c from the original equation and plug them into the quadratic formula.
2
2
+
6
+
4
=
0
2x^{2}+6x+4=0
2x2+6x+4=0
=
2
a={\color{#c92786}{2}}
a=2
=
6
b={\color{#e8710a}{6}}
b=6
=
4
c={\color{#129eaf}{4}}
c=4
=
−
6
±
6
2
−
4
⋅
2
⋅
4
√
2
⋅
2
x=\frac{-{\color{#e8710a}{6}} \pm \sqrt{{\color{#e8710a}{6}}^{2}-4 \cdot {\color{#c92786}{2}} \cdot {\color{#129eaf}{4}}}}{2 \cdot {\color{#c92786}{2}}}
x=2⋅2−6±62−4⋅2⋅4
brainliest and follow and thanks
