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kodGreya [7K]
2 years ago
7

SOMEONE ILL GIVE 100 POINTS

Mathematics
1 answer:
dsp732 years ago
4 0

Answer:

Step-by-step explanation:

1. ∠1 ≅∠3                  1.Given

2. m∠1 = m∠3           1. Given

3. ∠1 and ∠2 are linear pair   3.) linear pair

4. ∠1 an ∠2 are supplementary  4. Definition of linear pair

5. ∠1 + ∠2 = 180                           5. Definition of linear pair

6. ∠3 + ∠2 = 180                          6.substitution property of equality

7. ∠2 an ∠3 are supplementary  7. Proven

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Serena has $130 in her bank account . Her account is compounded quarterly for 2 years at a 9.4% interest rate . What is her tota
____ [38]
\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$130\\
r=rate\to 9.4\%\to \frac{9.4}{100}\to &0.094\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{quarterly, thus four}
\end{array}\to &4\\
t=years\to &2
\end{cases}
\\\\\\
A=130\left(1+\frac{0.094}{4}\right)^{4\cdot 2}\implies A=130(1.0235)^8
7 0
3 years ago
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Mazyrski [523]
The answer is......... 27
8 0
3 years ago
If z varies directly as x and z=30 when x=8 find z when x=4
dangina [55]
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8 0
3 years ago
Using the Law of Cosines, in triangle DEF, if e=18yd, d=10yd, f=22yd, find measurement of angle D
Ivahew [28]
Check the picture below.

\bf \textit{Law of Cosines}\\ \quad \\
c^2 = {{ a}}^2+{{ b}}^2-(2{{ a}}{{ b}})cos(C)\implies 
c = \sqrt{{{ a}}^2+{{ b}}^2-(2{{ a}}{{ b}})cos(C)}
\\\\\\
\cfrac{{{ a}}^2+{{ b}}^2-c^2}{2{{ a}}{{ b}}}=cos(C)\implies cos^{-1}\left(\cfrac{{{ a}}^2+{{ b}}^2-c^2}{2{{ a}}{{ b}}}\right)=\measuredangle C\\\\
-------------------------------\\\\
\begin{cases}
d=10\\
e=18\\
f=22
\end{cases}\implies cos^{-1}\left(\cfrac{{{ 18}}^2+{{ 22}}^2-10^2}{2(18)(22)}\right)=\measuredangle D

\bf \implies cos^{-1}\left(0.893\overline{93}\right)=\measuredangle D\implies 26.63^o\approx \measuredangle D

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3 years ago
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suter [353]
The answer is c eight units
6 0
3 years ago
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