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kompoz [17]
3 years ago
5

The table shows population data year 2000 118,000 2006 138,000 a. what is the percent of change to 2006 b. Use this percent of c

hange to predict the population in 2012

Mathematics
1 answer:
worty [1.4K]3 years ago
5 0
A) Now look, in the year 2000, the population is 118,000
In the year 2006 is 138,000
To find the percent change |Original Amt - New Amt|                                            --------------------------------       x100
                                                 Original Amt


So for this question you would do 118,00 - 138,000 (ignore the negativesss)

     and you get -20,000 (ignore the negatives) and then you get 20,000


Now, you have to do 20,000 divided by 118,000 x 100


20,000 divided by 118,000 and you get 0.169491525


Now you have to multiply 0.169491525 by 100

0.169491525 x 100 = 16.9491525

Round this and you get a 16.9% change.

b) To predict the population in 2012 you will have to do 138,000 + 16.9%

To calculate this you have to do this:
                                                 138,000 x 0.169 = 23322

Now add 23,322, to 138,000 and you get 161,322.

A) 16.9%

B) 161,322

hope this helped :)
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Answer:

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Step-by-step explanation:

We are given that the equation:

y=9000-2.4x

Models the relationsip between <em>y</em>, the number of unfilled seats in the stadium, and <em>x</em>, the number of cars in the parking lot.

We want to determine the number of cars in the parking lot when there are no unfilled seats in the stadium.

When there are no unfilled seats in the stadium, <em>y</em> = 0. Thus:

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Solve for <em>x</em>. Subtract 9000 from both sides:

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Divide both sides by -2.4:

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So, there will be 3,750 cars in the parking lot when there are no unfilled seats in the stadium.

4 0
3 years ago
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Step-by-step explanation:

Given:

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Anything to the multiple of zero is zero. Hence 0x = 0, and 0 ≠ 6

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