Question

Please help! Solve the following:

Answer 1

Answer:

n=10.

Step-by-step explanation:

$\frac{45}{n^{2}-3n-4 }$ - $\frac{3}{n-4}$ = $\frac{2}{n+1 }$

$\frac{45}{n^{2}-3n-4 }$ -  $\frac{3(n+1)}{(n+1)(n-4)}$ = $\frac{2(n-4)}{(n+1)(n-4) }$

$\frac{45}{n^{2}-3n-4 }$ -  $\frac{3n+3}{n^{2} -3x-4}$ = $\frac{2n-8}{n^{2} -3x-4 }$

45-3n-3=2n-8

45-3+8=5n

n=50/5=10