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PSYCHO15rus [73]
3 years ago
8

Please help! Solve the following:

Mathematics
1 answer:
mihalych1998 [28]3 years ago
4 0

Answer:

n=10.

Step-by-step explanation:

\frac{45}{n^{2}-3n-4 } - \frac{3}{n-4} = \frac{2}{n+1 }

\frac{45}{n^{2}-3n-4 } -  \frac{3(n+1)}{(n+1)(n-4)} = \frac{2(n-4)}{(n+1)(n-4) }

\frac{45}{n^{2}-3n-4 } -  \frac{3n+3}{n^{2} -3x-4} = \frac{2n-8}{n^{2} -3x-4 }

45-3n-3=2n-8

45-3+8=5n

n=50/5=10

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Answer:

a) 4/65 b) 13/65 c) 12/65 d) 19/65

Step-by-step explanation:

Probability is the likelihood or chance that an event might occur.

Probability = expected outcome of event/Total outcome of event

If a box contains cards bearing numbers from 6 to 70, the total outcome will be the total number present from 6 to 70 which is 65

a) The amount of one digit number we have are 4 i.e {6,7,8,9}. This will be our expected outcome in this case.

The probability that the number drawn bears a one digit number will be 4/65

b) For numbers divisible by 5, the numbers that are divisible by 5 from the number drawn are {10, 15, 20, 25, 30, 35, 40, 45, 50, 55, 60, 65, 70}

The total expected outcome in this case = 13

The probability that the number drawn is divisible by 5 = 13/65

c) For odd numbers less than 30, they are {7,9,11,13,15,17,19,21,23,25,27,29}

The total expected outcome in this case = 12

The probability that the number drawn are odd numbers less than 30 = 12/65

d) For composite number between 50 and 70, this are numbers that are within this range and they includes {51,52,53,54,55,56,57,58,59,60,61,62,63,64,65,66,67,68,69}

The total expected outcome in this case = 19

The probability that the number drawn are composite numbers between 50 and 70= 19/65

8 0
3 years ago
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Answer:

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