Answer:
6.3 moles
Explanation:
From the balanced equation of reaction:

2 moles of aluminium reacts with 3 moles of chlorine gas to form 2 moles of AlCl3.
Therefore, 1 mole of chlorine will require: 2 x 1/3 = 0.67 mole of aluminium.
Hence, 0.67 mole of aluminium will be needed for 1 mole of chlorine. If 7 moles of aluminium is present, then:
7 - 0.67 = 6.33 moles of aluminium will be left.
To the nearest 0.1, it means 6.3 moles of aluminium will be left.
Answer to the question
D. Petroleum
Answer:
1. Kc = [NO]⁴ [H₂O]⁶ / [NH₃]⁴ [O₂]⁵
2. Kc = [I₂]²
3. Kc = 1/[NH₃] [HCl]
Explanation:
The equilibrium constant (Kc) is equal to the product of the concentrations of the products raised to their stoichiometric coefficients divided by the product of the concentrations of the reactant raised to their stoichiometric coefficients. It only includes gases and aqueous species.
1. 4 NH₃(g) + 5 O₂(g) ↔ 4 NO(g) + 6 H₂O(g)
Kc = [NO]⁴ [H₂O]⁶ / [NH₃]⁴ [O₂]⁵
2. ZrI₄(s) ↔ Zr(s) + 2 I₂(g)
Kc = [I₂]²
3. NH₃(g) + HCl(g) ↔ NH₄Cl(s)
Kc = 1/[NH₃] [HCl]