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2 years ago

5

What may likely to happen with the snakes If the rats decrease in number?

2 answers:

lions [1.4K]2 years ago

5 0

If the number of rats decrease, snakes would look for another prey.

Solnce55 [7]2 years ago

5 0

The snakes will inter to cities and snakes may be one of the biggest physical factors of the displacement of people around the world. I hope it answers your question. Keep asking

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Name the type of equation then balance. Sn,(PO2)2 + Fe(CIO): - Sn(CIO3)2 + FePO,

erastovalidia [21]

Answer:

ionic compond

Explanation:

Sn(ClO3)4

5 0

2 years ago

A mixture of 15.0 g of the anesthetic halothane (C2HBrClF3 197.4 g/mol) and 22.6 g of oxygen gas has a total pressure of 862 tor

AlexFokin [52]

Answer : The partial pressure of $C_2HBrClF_3$ and $O_2$ are, 84 torr and 778 torr respectively.

Explanation : Given,

Mass of $C_2HBrClF_3$ = 15.0 g

Mass of $O_2$ = 22.6 g

Molar mass of $C_2HBrClF_3$ = 197.4 g/mole

Molar mass of $O_2$ = 32 g/mole

First we have to calculate the moles of $C_2HBrClF_3$ and $O_2$ .

$\text{Moles of }C_2HBrClF_3=\frac{\text{Mass of }C_2HBrClF_3}{\text{Molar mass of }C_2HBrClF_3}=\frac{15.0g}{197.4g/mole}=0.0759mole$

and,

$\text{Moles of }O_2=\frac{\text{Mass of }O_2}{\text{Molar mass of }O_2}=\frac{22.6g}{32g/mole}=0.706mole$

Now we have to calculate the mole fraction of $C_2HBrClF_3$ and $O_2$ .

$\text{Mole fraction of }C_2HBrClF_3=\frac{\text{Moles of }C_2HBrClF_3}{\text{Moles of }C_2HBrClF_3+\text{Moles of }O_2}=\frac{0.0759}{0.0759+0.706}=0.0971$

and,

$\text{Mole fraction of }O_2=\frac{\text{Moles of }O_2}{\text{Moles of }C_2HBrClF_3+\text{Moles of }O_2}=\frac{0.706}{0.0759+0.706}=0.903$

Now we have to partial pressure of $C_2HBrClF_3$ and $O_2$ .

According to the Raoult's law,

$p^o=X\times p_T$

where,

$p^o$ = partial pressure of gas

$p_T$ = total pressure of gas

$X$ = mole fraction of gas

$p_{C_2HBrClF_3}=X_{C_2HBrClF_3}\times p_T$

$p_{C_2HBrClF_3}=0.0971\times 862torr=84torr$

and,

$p_{O_2}=X_{O_2}\times p_T$

$p_{O_2}=0.903\times 862torr=778torr$

Therefore, the partial pressure of $C_2HBrClF_3$ and $O_2$ are, 84 torr and 778 torr respectively.

6 0

3 years ago

Gold is used for jewelry because it is malleable. This means it can be easily molded into different shapes. What is this an exam

anastassius [24]

Malleablity is a physical property so hence

D. Physical property is the answer

6 0

3 years ago

Please help!!! Stoich Question

Greeley [361]

Answer:

4KO₂ + 2CO₂ -> 2K₂CO₃ + 3O₂

<u> Step 1: Find the moles of O₂.</u>

n(O₂) = mass/ Mr.

n(O₂) = 100 / 32 = 3.125 mol

<u>Step 2: Find the ratio between KO₂ and O₂.</u>

<u>KO₂ </u> : <u> O₂</u>

4 : 3

4/3 : 1

(4*3125)/3 : 3.125

=4.167 mol of KO₂

Thus now we know, to produce 100 g of O₂, we need 4.167mol of KO₂

<u>Step 3: Find the mass of KO₂:</u>

<u />

mass = mol * Mr. (KO₂)

Mass = 4.167* 71.1

Mass = 296.25 g

5 0

2 years ago

1. Adrian has a rectangular block with the dimensions 3.5 in by 8.0 in by 5.5

miskamm [114]

Answer:

The density of the block is 2.827 grams/ cubic inch

Explanation:

The density of the block can be obtained by dividing the given mass of the block by its volume.

Density = mass / volume

The mass of the block given is 435.5 grams

The volume of the block can be obtained by using the formula:

Volume = Length X breadth X height

Volume = 3.5 X 8 X 5.5 = 154 $in^3$

There fore the density will be 435.5 / 154 = 2.827 grams/ cubic inch

8 0

3 years ago