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VLD [36.1K]
3 years ago
5

Acetic acid is a weak acid with a pKa of 4.76. What is the concentration of acetic acid in a buffer solution of 0.2M at pH 4.9.

Give your answer in M but as a numeral only to 3 decimal places.
Chemistry
1 answer:
masya89 [10]3 years ago
6 0

Answer:

0.084 M

Explanation:

Using the Henderson-Hasselbalch equation for a buffer ( a buffer is solution contain a weak acid and it conjugate base; the solution resist change in pH)

pH = pKa + log ( base/acid)

4.9 - 4.76 =log ( base / acid)

10^0.14 =  ( base / acid)

1.38 = (base / acid)

since there is 0.2 M in the buffer solution

the concentration of acid =  \frac{1}{(1+1.38)} × 0.2 = 0.084 M

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Answer:

Molecular formula is, C₃H₆O₃

Empirical formula (with the lowest subscript) → CH₂O

Explanation:

We assume that the organic acid's mass is 0.6 g. We know that, in 0.6 g of compound we have 0.24 g of C and 0.04 g of H, then, we have

(0.6 - 0.24 - 0.04) = 0.32 g of O.

We determine each mol:

0.24 g /12 g/mol = 0.02 mol of C

0.04 g/ 1g/mol = 0.04 mol of H

0.32 g/ 16 g/mol = 0.02 mol of O

1 mol of acid weighs 90 g/mol.

In 0.6 g of acid, we have, (0.6 g / 90g/mol) = 0.0067 moles

Let's find out the formula with rules of three:

0.00667 mol of acid have 0.02 moles of C

1 mol of acid may have (0.02 /0.00667) = 3 mol of C

0.00667 mol of acid have 0.04 moles of H

1 mol of acid may have (0.04 /0.00667) =  6 mol of H

0.00667 mol of acid have 0.02 moles of O

1 mol of acid may have (0.02 /0.00667) = 3 mol of O

Molecular formula is, C₃H₆O₃

We confirm by the molar mass: 12g/mol . 3 + 6 . 1g/mol + 32g/mol . 3 = 90

Empirical formula (with the lowest subscript) → CH₂O

5 0
3 years ago
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