3 consecutive odd integers...x, x + 2, and x + 4
x + x + 2 + x + 4 = 9
3x + 6 = 9
3x = 9 - 6
3x = 3
x = 1
x + 2 = 1 + 2 = 3
x + 4 = 1 + 4 = 5
so ur integers, from least to greatest, are : 1,3,5
Answer:
<h2>11</h2>
Step-by-step explanation:
Given h(t) = t²+t+ 12 and k(t) = √t-1, we are to find k(k.h)(10)
k{h(t)} = k{ t²+t+ 12}
Since k(t)= √t-1, we will replace the variable t in the function with t²+t+ 12
k(h(t)) = √{(t²+t+ 12)-1}
k(h(t)) = √t²+t+12-1
k(h(t)) = √t²+t+11
Substituting t = 10 into the resulting function;
k(h(10)) = √(10)²+(10)+11
k(h(10)) = √100+10+11
k(h(10)) = √121
<em>k(h(10))= 11</em>
<em></em>
<em>hence the value of (k compose h) (10) is 11</em>
Answer:
6 pretzels and 8 crackers
Step-by-step explanation:
Since his mom told him to give her the remaining, 6*4= 24 giving to his mom 2 pretzels and 8*4=32 so he has to give his mom 3 crackers. This way him and his friends have the same amount of snacks.
Hope you find it useful. Good night
Answer: B
Step-by-step explanation: I feel like it's b but it is too easy