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Nookie1986 [14]
3 years ago
5

What is 1.3h + 3.7 when h = 5

Mathematics
2 answers:
MakcuM [25]3 years ago
8 0

Answer:

10.2

Step-by-step explanation:

1.3h + 3.7

1.3 x 5 = 6.5

6.5 + 3.7 = 10.2

Anvisha [2.4K]3 years ago
3 0

Answer:

The answer is 10.20

Hope this helps!! :)

Step-by-step explanation:

1.3 * h(5)= 6.5

6.5 + 3.7= 10.20

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What is 2-1+5×4×11 order of operation ​
Alenkasestr [34]

Answer:

221

Step-by-step explanation:

2 - 1 + 5 · 4 · 11 = 2 - 1 + 20 · 11  = 2 - 1 + 220

2 - 1 + 220 = 1 + 220

7 0
3 years ago
Ride 7,500 meters on the first day and increase the distance by an additional
Bumek [7]
In the first 3 days, I think that Juanita will ride 12500? I'm not sure if that is right but I think it is.
8 0
3 years ago
Write 1,386 as the product of its prime factors. A. 2 x 3 x 3 x 7 x 11 B. 2 x 693 C. 2 x 3 x 7 x 33 D. 2 x 3 x 231
Olenka [21]
Hello there,

The "prime factor's" of 1,386 would be "2*3*3*7*11.

When we multiply those together. We get 1,386.

Hope this helps.

~Jurgen
5 0
3 years ago
Solve the 3 × 3 system shown below. Enter the values of x, y, and z. X + 2y – z = –3 (1) 2x – y + z = 5 (2) x – y + z = 4 (3)
Svet_ta [14]
<h2>Answer:</h2>

\boxed{x=1, \y=-1, \ z=2}

<h2>Step-by-step explanation:</h2>

We will use the Gaussian elimination method to solve this problem. To do so, let's follow the following steps:

Step 1: Let's multiply first equation by −2. Next, add the result to the second equation. So:

\begin{array}{ cccc }~~ x&+~~2~ y&-~~~~~ z&~=~-3\\&-~~~5~ y&+~~3~ z&~=~11\\~~ x&-~~~~~ y&+~~~~ z&~=~4\end{array}

Step 2: Let's multiply first equation by −1. Next, add the result to the third equation. Thus:

\begin{array}{ cccc }~~ x&+~~2~ y&-~~~~~ z&~=~-3\\&-~~~5~ y&+~~3~ z&~=~11\\&-~~~3~ y&+~~2~ z&~=~7\end{array}

Step 3: Let's multiply second equation by −35, Next, add the result to the third equation. Therefore:

\begin{array}{ cccc }~~ x&+~~2~ y&-~~~~~ z&~=~-3\\&-~~~5~ y&+~~3~ z&~=~11\\&&+~~\frac{ 1 }{ 5 }~ z&~=~\frac{ 2 }{ 5 }\end{array}

Step 4: solve for z, then for y, then for x:

\frac{ 1 }{ 5 } ~ z & = \frac{ 2 }{ 5 } \\ \\ \boxed{z & = 2}

-5y+3z &= 11\\-5y+3\cdot 2 &= 11\\ \\ \boxed{y &= -1}

By substituting y=-1 \ and \ z=2 into the first equation, we get the x. So:

x+2(-1)-2=-3 \\ \\ x-2-2=-3 \\ \\ \boxed{x=1}

6 0
3 years ago
Read 2 more answers
PLEASE help me with these thanks
Sladkaya [172]
7.) 6 + 9 = 15t - 6 = 9t + 2 = 11t
15t-4
Answer: A.)
8.) f^+2+3
f^5
Answer: A.)
9.)
144^14 = 1.6e30
144^220736
1.6e30/220736 = 7.9e25
/7.9e25 = 144^28
Answer: C.)
3 0
3 years ago
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