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alekssr [168]
3 years ago
12

I REALLY need help. I don't understand this at all and I need to pass. I suck at geometry.

Mathematics
2 answers:
Lisa [10]3 years ago
8 0
Answer: A=27\pi
ser-zykov [4K]3 years ago
3 0
Either as aforementioned above, or use \bf \textit{Area of a Ring}\\\\
A=\pi (R^2-r^2)\qquad 
\begin{cases}
R=\textit{longer radius}\\
r=\textit{shorter radius}
\end{cases}
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Step-by-step explanation:

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The Sum of the prime factor of 4275 is ?
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1. Find the Least Common Multiple of these two monomials:<br> See picture
gtnhenbr [62]

Answer:

<em>The last choice is correct</em>

<em />LCM=120a^4b^7c^5<em />

Step-by-step explanation:

<u>Least Common Multiple (LCM)</u>

To find the LCM we can follow this procedure:

List the prime factors of each monomial.

Multiply each factor the greatest number of times it occurs in either factor.

We have two monomials:

12a^4b^2c^5

40a^3b^7c^1

The prime factors of the first monomial are:

2^2,3,a^4,b^2,c^5

The prime factors of the second monomial are:

2^3,5,a^3b^7c^1

LCM = Multiply 2^3*3*5*a^4*b^7*c^5

These are all the factors the greatest number of times they occur.

Operating:

LCM=8*15*a^4*b^7*c^5

\boxed{LCM=120a^4b^7c^5}

The last choice is correct

3 0
4 years ago
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