Answer to the question is: I
Answer:
-10-(-6) = -10+6 = -4; A
Step-by-step explanation:
A square is a figure with four equal sides and four right angles.In a square the diagonals bisect at right angles .
In the above given options option A is the right answer.
If the diagonals of any parallelogram are perpendicular then the figure is not necessarily a square.
Diagonals are perpendicular in a rhombus too.
A square and Rhombus both have diagonals that are perpendicular.
So it is not a necessary condition for a parallelogram to be a square .
The other options are right .
So option B is the right option that if diagonals are perpendicular is not sufficient to prove the figure to be a square.
Answer:
C. x² + 7
Step-by-step explanation:
If f(x) = 2x² + 5 and g(x) = x² - 2, then
(f - g)(x) = f(x) - g(x)
= (2x² + 5) - (x² - 2)
= 2x² + 5 - x² + 2
= 2x² - x² + 5 + 2
= x² + 7
