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satela [25.4K]
3 years ago
6

Which could a translation result in? Select all that apply. a figure getting smaller a figure moving up a figure flipping upside

down a figure moving left a figure moving down
Mathematics
2 answers:
makkiz [27]3 years ago
8 0

Answer:

A figure moving up, a figure moving left, and a figure moving down.

Step-by-step explanation:

Translations are just moving things around in any direction.

ExtremeBDS [4]3 years ago
8 0
<h2>Answer:</h2>

The translation could result in:

  • a figure moving up.
  • a figure moving left.
  • a figure moving down.
<h2>Step-by-step explanation:</h2>

Translation--

It is  a transformation which changes the location of the figure but the shape and size of the figures remains the same i.e. the shape and size of the figure is retained after the transformation.

It either moves the figure up or down by some units.

i.e. f(x) → f(x)+k

then the graph of the function f(x) is shifted k units up is k>0

and k units down if k<0

Similarly it may shift the figure k units to the left or to the right.

i.e. if f(x) → f(x+k)

if k<0 then the function f(x) is shifted k units to the right.

and if k>0 then the function is shifted k units to the left.

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DENIUS [597]

2(7b + 5) will equal to 14b+10

Explanation:

2 times 7b= 14b

2 times 5= 10

4 0
2 years ago
Shane and Abha earned a team badge that required their team to collect no less than 2000 cans for recycling. Abha collected 178
Katarina [22]

Answer:

2x+178\geq 2000

Step-by-step explanation:

Let, the number of cans collected by Shane = x.

So, the number of cans collected by Abha = x + 178.

Since, at least 2000 cans are required to be collected.

Thus, we have the inequality,

Number of cans by Shane + Number of cans by Abha ≥ 2000.

i.e. x+(x+178)\geq 2000

i.e. 2x+178\geq 2000

Thus, the required inequality is 2x+178\geq 2000.

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3 years ago
Which expression can be used to find the surface area of the following square pyramid?
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Answer:

Step-by-step explanation:

The slant height of one side of this pyramid is 5, and the base of this side is 4.  Thus, the area of one slant side is (1/2)(5)(4) = 10 units^2.

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If you also want to include the base area, the total would be

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secant RM intersect secant RN at point R find the length of RQ if necessary round to the hundreds place.
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Step-by-step explanation:

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