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VLD [36.1K]
3 years ago
13

The quadratic function h(t)=-16.1t^2 + 150 models a balls height, in feet, over time, in seconds, after it is dropped from a 15

story building. From what height, in feet, was the ball dropped?
Mathematics
1 answer:
RideAnS [48]3 years ago
8 0

The ball is dropped from a building and the quadratic function which models the ball`s height is:

h ( t ) = - 16.1 t² + 150

We can find the initial height if we calculate h ( 0 ), or the height for : t = 0 sec.

h ( 0 ) = -16.1 · 0² + 150 = 0 + 150 = 150 ft

Answer:

The ball was dropped from 150 feet.

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Answer pls<br> thank you
frosja888 [35]

Answer:

d = 5/6t

Step-by-step explanation:

5 stories every 6 seconds

at 12 seconds, it would have travelled 10 seconds.

using this 2 data in this formula

(y-y1)/(x-x1) = (y2-y1)/(x2-x1)

Note : d = y, t = x;

d1 = 5, t1 = 6, d2 = 10, t2 = 12

we have

(d - 5)/(t-6) = (10-5)/(12-6)

(d - 5)/(t-6) = 5/6

d = 5/6(t-6) + 5

d = 5/6t -5+5

d = 5/6t

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Step-by-step explanation:

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3 years ago
Evaluate 1/4 c + 3d when c = 6 and d = 7
Naddika [18.5K]

           \rule{50}{1}\large\blue\textsf{\textbf{\underline{Question:-}}}\rule{50}{1}

       <em>Evaluate 1/4c+3d when c=6, and d=7.</em>

<em />

<em>         </em>\rule{50}{1}\large\blue\textsf{\textbf{\underline{Answer and how to solve:-}}}\rule{50}{1}

       Replace c with 6, and d with 7:-

     \Large\text{$\displaystyle\frac{1}{4} (6)+3(7)$}

\bigstar On simplification,

   \Large\text{$\displaystyle\frac{1}{4} \times\frac{6}{1}+21$}

\bigstar On further simplification,

    \Large\text{$\displaystyle\frac{6}{4} +21$}

\bigstar On further simplification,

     \Large\text{$\displaystyle\frac{6}{4}+\frac{84}{4}$}

\bigstar Adding the numerators,

\Large\text{$\displaystyle\frac{90}{4}$}

\bigstar Finally, Reducing the fraction:-

\Large\text{$\displaystyle\frac{45}{2}$}

\Uparrow \mathbb{OUR\:SIMPLIFIED\:EXPRESSION}

<h3>Good luck with your studies.</h3>

         \rule{50}{1}\smile\smile\smile\smile\smile\smile\rule{50}{1}

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