Answer:
800%
Step-by-step explanation:
<u>Volume of a square based pyramid</u>

where:
- a = base side length
- h = height
<u>Given values</u> for Pyramid A:
- a = 14 inches
- h = 6 inches
Substitute the given values into the formula to find the volume of <u>Pyramid A</u>:

Given:
- Volume of Pyramid B = 3136 in³
To find how many times bigger Pyramid B is than Pyramid A, divide the <u>volume of Pyramid B</u> by the <u>volume of Pyramid A</u>:

Therefore, the volume of Pyramid B is 8 times bigger than the volume of Pyramid A.
8 as a percentage is 800%, since 800/100 = 8.
Therefore, the volume of Pyramid B is 800% the volume of Pyramid A.
To verify this, find 800% of the volume of Pyramid A:
⇒ 800% of 392
= 800/100 × 392
= 8 × 392
= 3136
Answer:
Step-by-step explanation:
To find an equation of the sphere with center (4, −12, 8) and radius 10

intersection with xy-plane
Put z=0


(A circle with centre at (4,-12) and radius 6)
intersection with xz-plane
Put y =0


Sum of squares cannot be positive, so DNE
intersection with yz-plane
Put x=0


A circle in YZ plane with centre at y =-12 and z =8 and radius square root of 84
Answer:
50
Step-by-step explanation:
I took the test
Ok? Where’s the rest of the question.
Answer:
Step-by-step explanation:
Day 1 = 2 birds
day 2 = 3 birds
day 3 = 9 birds
day 4 = 8 birds
day 5 = 1 bird
On day 1 the points are (1,2)
On day 5 the points are (5,1)
(I am picking these for the points because I don't know your options for the selecting area.)
we use this formula y2-y1/x2-x1
2-5/1-1
3/0
our answer is infinite which is the relation and this is an infinite function