2*10^6 + 6*10^5 + 3*10^3 +9*10^1 +4*10^0
see expanded form is adding the digits together. and it would be what ever one number is times 10 to the power of how many digits are after that number. you skip the 0's though. hope this helps
Answer:
its 3.05
Step-by-step explanation:
Your answer will be 1/10. you divide 3 by the numerator and denominator <span />
24= 3*2^3
88= 11*2^3
664= 83*2^3 -> 83=11+72 = 11 + 2^3*3^2
664=2^3 (11+2^3*3^2) = 88 +(2^3*2^3*3^2) = 88 +(24^2)
8408= 1051 * 2^3 -> 1051= 83+968 -> 968 = 2^3 * 11^2
8408= 2^3 (83+2^3*11^2) = 664 +(2^3*2^3*11^2) = 664 +(88^2)
So:
a(n) = a(n-1) + a(n-2)^2
Lets check: 88+24^2= 664
664+88^2= 8408
Answer:
-9
Step-by-step explanation:
you'd add 2 to the -11 which would equal -9 and leave you with x=-9
