I hope this help you I gess 16
Answer:
The requirements that are necessary for a normal probability distribution to be a standard normal probability distribution are <em>µ</em> = 0 and <em>σ</em> = 1.
Step-by-step explanation:
A normal-distribution is an accurate symmetric-distribution of experimental data-values.
If we create a histogram on data-values that are normally distributed, the figure of columns form a symmetrical bell shape.
If X
N (µ, σ²), then
, is a standard normal variate with mean, E (Z) = 0 and Var (Z) = 1. That is, Z
N (0, 1).
The distribution of these z-variates is known as the standard normal distribution.
Thus, the requirements that are necessary for a normal probability distribution to be a standard normal probability distribution are <em>µ</em> = 0 and <em>σ</em> = 1.
0 + -4 = -4
the 0 has no value and cannot add anything on top of the -4
So -4 stays the same:)
Answer = -4
Good Luck! :)
5 + 10^2 - 3 ( 12 - 8 ) = 93 12 - 8 = 4 then do 3 x 4 which = 12 and then add 5 to 10^2 which = 105 105 - 12 = 93
Answer:
70°
Step-by-step explanation:
∠A =112°,
Exterior angle to angle B is 2x, therefore ∠B = 180 -2x (angle on straight line)
Exterior angle to angle C is 2x + 12, therefore ∠C = 180 -(2x +12) (angle on straight line) = 180 - 12 -2x = 168 - 2x
∠A + ∠B + ∠C = 180 (sum o angles in a triangle)
112 + 180 - 2x + 168 - 2x = 180
460 - 4x = 180
4x = 460 - 180 = 280
x = 280/4 = 70
x = 70°