11.7
Formula: a^2 + b^2 = c^2
so substitute the numbers like this:
10^2 + 6^2 = c^2
both 10^2 and 6^2 are perfect squares:
10 × 10= 100 and 6 × 6= 36
100 + 36= c^2
add:
100 + 36 =
136 = c^2
now in order to get rid of the squared, you put it into a radical:
√136 = √c^2
note: whatever you do on one side, you do to the other
it's easier to use the calculator for this so put √136 and you're gonna get 11.66
since it's asking you to round it to the nearest tenth:
11.66 = 11.7
sorry if the explanation is kinda long ✋ i tried explaining it better in the end but i failed
Yes it is indeed nothing else can be done to this problem
Answer:
<u>0.04kg</u>
Step-by-step explanation:
Kinetic energy Formula: eK=0.5×m×v²
to work out mass
we can rearrange the formula and make it:
~m=eK÷(0.5×v²)
now insert the missing digits into the formula:
m=200÷(0.5×100²)
work it out, and you get your answer
m=0.04kg
Hopefully this helped-have a good day)
Im imperfect linear :( line grafh
Answer:
The speed of the first train is 45 mph and the speed of the second train is 75 mph
Step-by-step explanation:
Let x represent the speed of the first train in mph. Since the second train, is 30 mph faster then the first, therefore the speed of the second train is (x + 30).
The first train leaves at 1:00 pm, therefore at 6:00 pm, the time taken is 5 hours. Therefore the distance covered by the first train at 6:00 pm = x mph * 5 hours = 5x miles
The second train leaves at 3:00 pm, therefore at 6:00 pm, the time taken is 3 hours. Therefore the distance covered by the second train at 6:00 pm = (x + 30) mph * 3 hours = (3x + 90) miles
Since the second train overtakes the first at 6:00 pm, hence:
3x + 90 = 5x
2x = 90
x = 45
Therefore the speed of the first train is 45 mph and the speed of the second train is 75 mph (45 mph + 30 mph).
