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denis23 [38]
2 years ago
9

A twelve-sided die with sides labeled 1 through 12 will be rolled once. Each number is equally likely to be rolled.

Mathematics
1 answer:
kykrilka [37]2 years ago
6 0

Answer:

1/6

..................

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Two hundred fifty people were surveyed to determine their favorite mode of transportation. What number of people chose walking?
4vir4ik [10]

Answer:

14

Step-by-step explanation:

6 0
3 years ago
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What is an equation of the line that passes through the points (-3, 8) and (4, 1)?
butalik [34]

Answer:

The equation of the line is:

y=-x+5

Step-by-step explanation:

Given the points

  • (-3, 8)
  • (4, 1)

Finding the slope between the points

\left(x_1,\:y_1\right)=\left(-3,\:8\right),\:\left(x_2,\:y_2\right)=\left(4,\:1\right)

\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}

m=\frac{1-8}{4-\left(-3\right)}

m=-1

Using the point-slope form of the line equation

y-y_1=m\left(x-x_1\right)

where m is the slope

substituting the values m = -1 and the point (-3, 8)

y-y_1=m\left(x-x_1\right)

y-8=-1\cdot \left(x-\left(-3\right)\right)

y-8=-\left(x+3\right)

Add 8 to both sides

y-8+8=-\left(x+3\right)+8

y=-x+5

Therefore, the equation of the line is:

y=-x+5

8 0
2 years ago
Without the use of a calculator, calculate 77^2−23^2.
stepan [7]

Answer:

5400

Step-by-step explanation:

4 0
3 years ago
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Solve the problem. Round to the nearest cent.
Alex17521 [72]

1986*1.04^(23) = 4894.93


4894.93-1986 = 2908.93


Answer is A


7 0
3 years ago
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In a class of 100 students, 25 have hardcover and 75 students have paperback textbooks. If you randomly choose 15 students in th
Gnom [1K]

Answer:

23.72% probability that 3 of them have hardcover texts.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

The order in which the students are chosen is not important. So we use the combinations formula to solve this question.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

If you randomly choose 15 students in this class, find the probability that 3 of them have hardcover texts.

Desired outcomes:

3 with hardcover texts, from a set of 25.

15-3 = 12 with paperback texts, from a set of 75. So

D = C_{25,3}*C_{75,12} = \frac{25!}{3!(22)!}*\frac{75!}{12!(63)!} = 6 \times 10^{16}

Total outcomes:

15 students from a set of 100. So

T = C_{100,15} = \frac{100!}{15!85!} = 2.53 \times 10^{17}

Probability:

P = \frac{D}{T} = \frac{6 \times 10^{16}}{2.53 \times 10^{17}} = 0.2372

23.72% probability that 3 of them have hardcover texts.

7 0
2 years ago
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