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Alecsey [184]
3 years ago
12

allison burns 15 calories per minute on the elliptical and 12 calories per minute on the treadmill. If she spent one hour at the

gym on these two machines and burned a total of 774 calories, how long did she spend on the elliptical?
Mathematics
2 answers:
kaheart [24]3 years ago
7 0

Answer:

25.38

Step-by-step explanation:

i did it quick so its prob wrong

Mekhanik [1.2K]3 years ago
7 0

Answer:

The rate of change is obviously that term that describe the change over a certain period. In this problem, we are given with the condition that LaToya is able to burn 20 calories per minute. Therefore, the rate of change is 20 calories per minute.   Step-by-step explanation:

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The company that owns the telescope gives a discount of $8 off the rental fee for every rental hour after the first two hours. T
NISA [10]

Answer:

20

Step-by-step explanation:Please give me a brainly

4 0
3 years ago
Translate the sentence into an inequality twice the difference of a number and 6 is at least -22 use the variable x for the unkn
almond37 [142]

Answer:

2(n - 6) >= 22

Step-by-step explanation:

2n - 12 >= 22

2n >= 22+12

2n >= 34

n >= 34/2

n >= 17

5 0
3 years ago
Help me with these 3 and explain too thank you :))
xz_007 [3.2K]

Answer:

1) 25

2) 2

3) f(g(1)) = 42

Step-by-step explanation:

1) Given that f(x) = 4x^2  + 9

If x = -2

f(-2) = 4(-2)^2 + 9

f(-2) = 4(4) + 9

f(-2) = 16 + 9

f(-2) = 25

2) Given that f(x) = 4x - 6

y = 4x - 6

Replace y  with x

x = 4y - 6

MAke y the subject of the forfmula

4y = x+ 6

y = (x+6)/4

SInce x = 2

f^(-1)(2) = (2+6)/4

f^(-1)(2) = 8/4 = 2

3) If f(x) = 6x and g(x) = x+6

f(g(x)) = f(x+6)

f(x+6) = 6(x+6)

Since x = 1

f(g(1)) = 6(1+6)

f(g(1)) = 6(7)

f(g(1)) = 42

5 0
3 years ago
Can someone please help me i dont understand this at all
goblinko [34]

Answer:

D.

40 x 6.4 = 256

256/128=2 so 2 gallons.

Step-by-step explanation:

5 0
3 years ago
Graph y= x−2.<br> PLZZ HELP
nataly862011 [7]

Explanation: To graph the equation y = x - 2, the idea is simple.

We pick three values for <em>x</em>, plug them into the

equation, and find the corresponding values for <em>y</em>.

In order to do this in an organized way, we set up a chart.

Down the left side we make a column for our x's, down the right side we make a column for our y's, and in the middle we make a column for the side of the equation that contains the <em>x</em>, in this case, x - 2.

So reading the chart from left to right, we have our <em>x</em> or what we plug into the equation, then we have the x - 2 or what happens to the x when we plug it into the equation, and finally we have our <em>y</em> or what we end up with after plugging <em>x</em> into the equation.

So our first step in filling out the chart is choosing

the x's that we want to plug into the equation.

When graphing lines, I always choose three x's,

a positive number, zero, and a negative number.

The easiest numbers to pick are usually 1, 0, and -1.

So for 1, we plug a 1 into the equation for <em>x</em>

and we have y = (1) - 2 or -1

For 0 we plug a 0 into the equation for <em>x</em>

and we have y = (0) - 2 or -2.

For -1 we plug a -1 into the equation for <em>x</em>

and we have y = (-1) - 2 or -3.

So our points are (1, -1), (0, -2), and (-1, -3).

I looked at the x and y column to find those points.

Since our domain is all real numbers, we can connect these points based on the pattern that they are forming on the graph which is a line.

5 0
3 years ago
Read 2 more answers
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