Complete question :
designs a board game in which a card is drawn on each turn. • A blue card means move forward 4 squares. • A red card means move back 6 squares. Liam suggests adding some other cards to Sia's game Part A Liam explains that drawing a yellow card is equivalent to drawing a blue card followed by a red card. How many spaces forward or backward does a player move after drawing a yellow card? Justify your answer.
Answer:
2 squares backward
Step-by-step explanation:
Given the rule :
Blue card = 4 squares forward
Red card = 6 squares backward
Yellow card = drawing a blue followed by a red
Spaces moved after drawing a yellow card:
Yellow equals :
Blue = + 4 squares ; then
Red = - 6 squares
Net total movement :
Blue + red
+4 + (-6)
4 - 6
- 2
2 squares backward
ok so first we would do the function d(x) = 3(8)+2
which when solved turns out to be 26
we would then do the function h(x) = 2(26) +7
which when solved turns out to be 59
so he would need 59 dollars for the donuts
The <em>proposed</em> design of the atrium (<em>V < V'</em>) is possible since its volume is less than the <em>maximum possible</em> atrium.
<h3>Can this atrium be built in the rectangular plot of land?</h3>
The atrium with the <em>maximum allowable</em> radius (<em>R</em>), in feet, is represented in the image attached. The <em>real</em> atrium is possible if and only if the <em>real</em> radius (<em>r</em>) is less than the maximum allowable radius and therefore, the <em>real</em> volume (<em>V</em>), in cubic feet, must be less than than <em>maximum possible</em> volume (<em>V'</em>), in cubic feet.
First, we calculate the volume occupied by the maximum allowable radius:
<em>V' =</em> (8 · π / 3) · (45 ft)³
<em>V' ≈</em> 763407.015 ft³
The <em>proposed</em> design of the atrium (<em>V < V'</em>) is possible since its volume is less than the <em>maximum possible</em> atrium. 
To learn more on volumes, we kindly invite to check this verified question: brainly.com/question/13338592
Answer: -121
Step-by-step explanation:
Answer with explanation:
Given : The computed r -value = 0.45
Sample size : n=18
Degree of freedom : 
Now, the critical value for Pearson correlation coefficient for a two-tailed test at a .05 level of significance will be :
( by critical correlation coefficient table)
Since ,
i.e. 0.45>0.468 , then we say that his Pearson correlation coefficient is not significant for a two-tailed test at a .05 level of significance.