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melamori03 [73]
3 years ago
11

Hard math question please dont paste a link

Mathematics
1 answer:
const2013 [10]3 years ago
6 0

Answer:

3x-1

Step-by-step explanation:

If you need an explanation let me know

Please mark as brainliest

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PLEASE HELP 100 POINTS 100 100 100 PLEASSSSE
Oksi-84 [34.3K]

Answer:

b

Step-by-step explanation:

5 0
3 years ago
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Monique's son just turned 2 years old and is 34 inches tall. Monique heard that the average boy will grow approximately 2 5/8 in
tatuchka [14]

Answer:

The equation representing how old Monique son is \mathbf{a = 2 + \dfrac{8}{21}(q-34)}

Step-by-step explanation:

From the given information:

A linear function can be used to represent the constant growth rate of Monique Son.

i.e.

q(t) = \hat q \times t + q_o

where;

q_o = initial height of Monique's son

\hat q = growth rate (in)

t = time

So, the average boy grows approximately 2 5/8 inches in a year.

i.e.

\hat q = 2 \dfrac{5}{8} \ in/yr

\hat q =  \dfrac{21}{8} \ in/yr

Then; from the equation q(t) = \hat q \times t + q_o

34 = \dfrac{21}{8} \times 0 + q_o

q_o = 34\  inches

The height of the son as a function of the age can now be expressed as:

q(t) = \dfrac{21}{8} \times t + 34

Then:

Making t the subject;

q - 34 = \dfrac{21}{8} \times t

t = \dfrac{8}{21}(q-34)

and the age of the son  i.e. ( a (in years)) is:

a = 2 + t

So;

\mathbf{a = 2 + \dfrac{8}{21}(q-34)}

SO;

if q (growth rate) = 50 inches tall

Then;

\mathbf{a = 2 + \dfrac{8}{21}(50-34)}

\mathbf{a = 2 + \dfrac{8}{21}(16)}

a = 2 + 6.095

a = 8.095 years

a ≅ 8 years

i.e.

Monique son will be 8 years at the time Monique is 50 inches tall.

8 0
2 years ago
Two numbers that add to -0.5 and multiply to 1
snow_lady [41]
X +(1/x) = -0.5 has no real solutions.

There are no real numbers that meet your requirements.

_____
The two complex numbers that meet your requirement are
  -1/4 +i√(15/16), -1/4 -i√(15/16)
4 0
3 years ago
PLS HELP I WILL MARK BRAINLIEST
tigry1 [53]

Answer:

5x<50

Step-by-step explanation:

8 0
3 years ago
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Find the perimeter of a rectangle that is 5three fourths in. by 7 in.
dimulka [17.4K]
The perimeter is 25 2/4 in.
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