Answer:
13 and -14 satisfy this condition
Step-by-step explanation:
Let's represent that number as x
and the square of x is x^2
So,
x + x^2 = 182
Subtract 182 from both sides
x + x^2 - 182 = 182 - 182
x + x^2 - 182 = 0
rearrange the quadratic equation
x^2 + x -182 = 0
let's use the quadratic formula
or 
a = 1, b = 1, c = -182
or 
or 
or 
or 
or 
13 or - 14
Lets check
13 + 13^2 = 13 + 169
= 182
Also,
-14 + (-14^2) = -14 + 196
= 182
Follow pemdas. Evaluate operations in parentheses first.
2*(-7)+14-4
Then multiply
-14+14-4
Then add and subtract from left to right
-14+14=0
0-4=-4
Final answer: -4
Answer:
Step-by-step explanation:
We'll call the 2 numbers x and y. Starting with the last part of that first sentence "one number is 10 times the other number" can be written, in algebraic form:
y = 10x
Now on to the first statement about the numbers: "twice their sum" is 2(x + y) and "equals their product" is = xy. Putting that all together:
2(x + y) = xy and we know that y = 10x so
2(x + 10x) = x(10x) and
and
and
x(10x - 22) = 0 so
x = 0 or 10x - 22 = 0 which makes
x equal to 
So x = 2.2 and y = 22.
Answer:
Hey there!
a)
10x-1=4x+2
6x-1=2
6x=3
x=1/2 cm.
10x-1=4 cm.
So the width of the rectangle is 10/4, or 2.5 cm.
b)
l=3w
2l+2w=24
2(3w)+2w=24
6w+2w=24
8w=24
w=3
l=9
The are is 27 units squared.
Let me know if this helps :)
Answer:
Step-by-step explanation:
X= (-7+radical 13)/6
X=(-7-radical 13)/6
