Answer:
Explanation:
Take sum of torques at the point the step touches the wheel, that eliminates two torques
Σ
Since we are looking for when the wheel just starts to rise up N-> 0 so no torque due to normal force
The perpendicular lever arm for the F force is R-h
And the T of gravity according to the image
Σ
Answer:
Explanation:
Radius of ring r = .05 m
Electric field due to a uniformly charged ring
E = k Q x / ( x² + r² )³/² ; Q is charge on the ring , x is distance of point from the center of the ring and r is radius of the ring
electric field due to first ring at middle point or at x = 7.5 cm
E = 9 x 10⁹ x 33 x 10⁻⁹ x 7.5 x 10⁻² / ( 7.5² + 5² )³/² x 10⁻³
= 9 x 10⁹ x 33 x 10⁻⁹ x 7.5 / ( 7.5² + 5² )³/² x 10⁻¹
= 9 x 10⁹ x 33 x 10⁻⁹ x 7.5 / 73.23
= 30.41 N/C
The same field will be created by the other ring at the middle point because charge on the ring is same in magnitude . Due to negative charge on the second ring , field due to both the rings will align in the same direction.
Total field = 2 x 30.41
= 60.82 N/C
The force applied on the spring to stretch it is 13.2 N.
Hooke's law is a law of elasticity discovered by the English scientist Robert Hooke in 1660 that states that the displacement or size of a deformation is directly proportional to the deforming force or load for relatively small deformations of an object. When the load is removed under these conditions, the object returns to its original shape and size.
According to Hooke's law, F = k*e
where F is the force on the spring
k is force constant
and e is extension
F = (110)*(0.12)
F = 13.2 N
For more information on Hooke's law, visit :
brainly.com/question/13348278
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