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kondaur [170]
3 years ago
14

A night lamp uses a 30 W bulb. If it is left on continuously for 8 hours, how much energy will it use?

Physics
2 answers:
fiasKO [112]3 years ago
4 0
My guess is that it will use 240 w
11111nata11111 [884]3 years ago
3 0
.24 is the answer, I don't know why, it just be.
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5 points
Drupady [299]

Answer:

distance is not a vector. it is scalar

5 0
3 years ago
7. Explain why observations of comets and shooting stars presented challenges to ancient astronomers using
Lelu [443]

According to Ptolemy's model, he, too, believed in a geocentric Universe and that the planets and stars were perfect spheres, though Earth itself was not.

He further thought that the movements of the planets and stars must be circular since they were perfect and, if the motions were circular, then they could go on forever.

<h3>What is comets and shooting stars?</h3>

Shooting stars are very different from comets, although the two can be related. A Comet is a ball of ice and dirt, orbiting the Sun (usually millions of miles from Earth). ... A shooting star on the other hand, is a grain of dust or rock (see where this is going) that burns up as it enters the Earth's atmosphere.

Learn more about ptolemy's model:

brainly.com/question/12639459

3 0
2 years ago
A current of 17 A flows through a resistor of 10 2. What is the voltage<br> across the resistor
zhenek [66]
Ohms law V = IR

17 x 10 = 170V
5 0
2 years ago
Suppose you have two meter sticks, one made of steel and one made of invar (an alloy of iron and nickel), which are the same len
Mekhanik [1.2K]

Answer:

  • The difference in length for steel is 2.46 x 10⁻⁴ m
  • The difference in length for invar is 1.845 x 10⁻⁵ m

Explanation:

Given;

original length of steel, L₁ = 1.00 m

original length of invar, L₁ = 1.00 m

coefficients of volume expansion for steel, \gamma_{st.} =  3.6 × 10⁻⁵ /°C

coefficients of volume expansion for invar, \gamma_{in.} =  2.7 × 10⁻⁶ /°C

temperature rise in both meter stick, θ = 20.5°C

Difference in length, can be calculated as:

L₂ = L₁ (1 + αθ)

L₂  = L₁ + L₁αθ

L₂  - L₁ = L₁αθ

ΔL = L₁αθ

Where;

ΔL is difference in length

α is linear expansivity = \frac{\gamma}{3}

Difference in length, for steel at 20.5°C:

ΔL =  L₁αθ

Given;

L₁ = 1.00 m

θ = 20.5°C

\alpha = \frac{\gamma}{3} = \frac{3.6*10^{-5}}{3} = 1.2*10^{-5} /^oC

ΔL  = 1 x 1.2 x 10⁻⁵ x 20.5 = 2.46 x 10⁻⁴ m

Difference in length, for invar at 20.5°C:

ΔL =  L₁αθ

Given;

L₁ = 1.00 m

θ = 20.5°C

\alpha = \frac{\gamma}{3} = \frac{2.7*10^{-6}}{3} = 0.9*10^{-6}/^oC

ΔL  = 1 x 0.9 x 10⁻⁶ x 20.5 = 1.845 x 10⁻⁵ m

8 0
3 years ago
After your school's team wins the regional championship, students go to the dorm roof and start setting off fireworks rockets. T
PIT_PIT [208]

Answer:

160 m

Explanation:

The intensity, I, of the sound is inversely proportional to the square of the distance, r, from the source.

I\propto \dfrac{1}{r^2}

Hence,

I_1r_1^2 = I_2r_2^2

r_2 = r_1\sqrt{\dfrac{I_1}{I_2}}

From the question, I_2 is half of I_1

r_2 = r_1\sqrt{\dfrac{I_1}{0.5I_1}}

r_2 = r_1\sqrt{2}

r_2 = 113\text{ m}\sqrt{2} = 160 \text{ m}

3 0
3 years ago
Read 2 more answers
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