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olga nikolaevna [1]
3 years ago
10

What causes an atom to be neutral? Equal number of protons and neutrons Equal distance between the nucleus and electrons Equal n

umber of electrons and protons Equal distribution of electrons
Physics
1 answer:
pishuonlain [190]3 years ago
3 0
C. Equal number of electrons and protons
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How to measure the speed of sound in air?
Leona [35]

STEP ONE:


Let  you and your friend stand as far away as possible from a large reflecting wall and clap your hands rapidly at a regular rate.  


STEP TWO:


Adjust this rate until each clap just coincides with the return of an echo of its predecessor, or until clap and echo are heard as equally spaced.


STEP THREE:


Use a stopwatch to find the time between claps, t. Make a rough measurement of distance to the wall, s. Thus the speed of sound, v = 2s/t

8 0
3 years ago
Does a heavier object or a lighter object experience a greater gravitational<br> force?
aalyn [17]

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5 0
3 years ago
A rope of total mass m hnd length L is suspended vertically with an object of mass M suspended from the lower end. Find an expre
pantera1 [17]

Answer:

Part a)

v = \sqrt{xg + \frac{MLg}{m}}

Part b)

t = 12 s

Explanation:

Part a)

Tension in the rope at a distance x from the lower end is given as

T = \frac{m}{L}xg + Mg

so the speed of the wave at that position is given as

v = \sqrt{\frac{T}{\mu}}

here we know that

\mu = \frac{m}{L}

now we have

v = \sqrt{\frac{ \frac{m}{L}xg + Mg}{m/L}

v = \sqrt{xg + \frac{MLg}{m}}

Part b)

time taken by the wave to reach the top is given as

t = \int \frac{dx}{\sqrt{xg + \frac{MLg}{m}}}

t = \frac{1}{g}(2\sqrt{xg + \frac{MLg}{m}})

t = \frac{2}{9.8}(\sqrt{(39.2\times 9.8) + \frac{8(39.2)(9.8)}{1}})

t = 12 s

4 0
3 years ago
If Scoobie could drive a Jetson's flying car at a constant speed of 450.0 km/hr across oceans and space, approximately how long
vladimir2022 [97]

Answer:

The value is t = 3.6 \  days

Explanation:

From the question we are told that

The speed is v  =  450.0 km/h

The radius of the earth is R =  6200 \  km

Generally the circumfernce of the earth is mathematically evaluated as

C =  2\pi  R

=> C =   2 * 3.142 *   6200

=> C =  38960.8 \ km

Generally the time taken is mathematically represented as

t =  \frac{38960.8}{450.0}

         t = 86.6 \  hr

Converting to days

         t = \frac{86.6}{24}

=>       t = 3.6 \  days

7 0
3 years ago
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