Answer:
Hydrostatic Force = 35.28KN
Step-by-step explanation:
To solve this question, let's consider integrating the hydrostatic force from the top of the triangle to the bottom.
Formula for a thin horizontal slice of the triangle the force is;
δF=ρgxwδx
Where w is width of triangle; ρ is density of water and g is acceleration due to gravity
At depth x, the width of the triangle is w=2/3x.
Thus, F = (3,0)∫)ρgxwδx
=(2/3)ρg[(3,0)∫)x²δx]
= integrating, we have;
F = (2/3)ρg[(3³/3) - (0³/3)]
F = (2/5)ρg [27/3] = (2/5)(1000)(9.8)(9) = 35280 N = 35.28 KN
Answer:
Step-by-step explanation:
The formula of volume of cone is
V=\frac{1}{3}\pi r^{2} h
where, r is the radius
we have given diameter = 12 =2r
r=6 ft
h is the height h=6 ft
\pi =3.14
Substitute the value in the formula,
V=\frac{1}{3}\pi r^{2} h
V=\frac{1}{3}\times (3.14)\times 6^{2}\times 6
V=\frac{1}{3}\times 3.14\times 36\times 6
V=226.08 ft^3
Therefore, The volume of cone is 226.08 cubic ft.
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1,431 pounds to go all the way around Wilmas house
Answer:
450,000 codes
Step-by-step explanation:
Number of digits in the access code = 6
Conditions:
- First digit cannot be 2
- Last digit must be odd
Since, there are 10 digits in total from 0 to 9 and first digit cannot be 2, there are 9 ways to fill the place of first digit.
Last digit must be odd. As there are 5 odd digits from 0 to 9, there are 5 ways to fill the last digit.
The central 4 digits can be filled by any of the 10 numbers. So, each of them can be filled in 10 ways.
According to the fundamental rule of counting, the total possible codes would be the product of all the possibilities of individual digits.
Therefore,
Number of possible codes = 9 x 10 x 10 x 10 x 10 x 5 = 450,000 codes
Hence, 450,000 different codes are possible for the lock box
Answer:
34
Step-by-step explanation:
4+15+15
