Answer:
(- 7, - 3) and (7, - 3)
Step-by-step explanation:
The best way to do this is to sketch the graph...when dealing with reflection in the y axis, the value for y remains the same and the value for x becomes negative if it was positive or becomes positive if it was negative
Send a picture of it ok then i answer
Answer:
2p² + 14p + 2
Step-by-step explanation:
Given that;
C= 1+p²+3p
B=2p+6p
The expression that equals to : 2C - -B will be;
2{1+p²+3p} - {-2p-6p}
2+2p²+6p + 2p + 6p
2p² + 6p +2p +6p +2
2p² + 14p + 2
SO what you need to do is:
<span>Start with |f(x) - 3| < 0.4
and plug in f(x) = x+1
to get
|f(x) – 3| < 0.4
|x+1 – 3| < 0.4
|x - 2| < 0.4
-0.4 < x - 2 < 0.4
-0.4+2 < x < 0.4+2
1.6 < x < 2.4
So delta would be 2.3
Hope this is what you were looking for
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