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Ugo [173]
2 years ago
10

A number of conditions are required for a population to be in Hardy-Weinberg equilibrium. Which of the following are correct des

criptions of the conditions that must be met? Check all that apply.
A. no mutations

B. random mating

C. small population

D. migration or gene flow

E. occurrence of mutations

F. no natural selection
Physics
2 answers:
S_A_V [24]2 years ago
7 0

Answer: A, B, F

Explanation:

Marina CMI [18]2 years ago
3 0

There are total 5 number of conditions which are required in Hardy Weinberg Equilibrium to be established, of which no mutations, random mating and no natural selection, are given in the option.

Answer: A, B, F

<u>Explanation: </u>

To acquire the Hardy Weinberg equilibrium in the specified population, it must be kept in check for the random mating as given in the option. Other conditions are to have a large population which are free to mate and breed. Then there must be no allelic change in frequency as a result of mutation and mutation is allowed. The gene flow or the immigration of population or the emigration is not allowed. There must be no natural selection.  

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A ball is launched from ground level at 20 m/s at an angle of 40° above the
DedPeter [7]

(a) The ball's height <em>y</em> at time <em>t</em> is given by

<em>y</em> = (20 m/s) sin(40º) <em>t</em> - 1/2 <em>g t</em> ²

where <em>g</em> = 9.80 m/s² is the magnitude of the acceleration due to gravity. Solve <em>y</em> = 0 for <em>t</em> :

0 = (20 m/s) sin(40º) <em>t</em> - 1/2 <em>g t</em> ²

0 = <em>t</em> ((20 m/s) sin(40º) - 1/2 <em>g t</em> )

<em>t</em> = 0   or   (20 m/s) sin(40º) - 1/2 <em>g t</em> = 0

The first time refers to where the ball is initially launched, so we omit that solution.

(20 m/s) sin(40º) = 1/2 <em>g t</em>

<em>t</em> = (40 m/s) sin(40º) / <em>g</em>

<em>t</em> ≈ 2.6 s

(b) At its maximum height, the ball has zero vertical velocity. In the vertical direction, the ball is in free fall and only subject to the downward acceleration <em>g</em>. So

0² - ((20 m/s) sin(40º))² = 2 (-<em>g</em>) <em>y</em>

where <em>y</em> in this equation refers to the maximum height of the ball. Solve for <em>y</em> :

<em>y</em> = ((20 m/s) sin(40º))² / (2<em>g</em>)

<em>y</em> ≈ 8.4 m

8 0
2 years ago
Two sound waves have equal displacement amplitudes, but wave 1 has two-thirds the frequency of wave 2. What is the ratio of the
zlopas [31]

Answer:

\dfrac{I_1}{I_2}=\dfrac{4}{9}

Explanation:

c = Speed of wave

\rho = Density of medium

A = Area

\nu = Frequency

\nu_1=\dfrac{2}{3}\nu_2

Intensity of sound is given by

I=\dfrac{1}{2}\rho c(A\omega)^2\\\Rightarrow I=\dfrac{1}{2}\rho c(A2\pi \nu)^2

So,

I\propto \nu^2

We get

\dfrac{I_1}{I_2}=\dfrac{\nu_1^2}{\nu_2^2}\\\Rightarrow \dfrac{I_1}{I_2}=\dfrac{\dfrac{2}{3}^2\nu_2^2}{\nu_2^2}\\\Rightarrow \dfrac{I_1}{I_2}=\dfrac{4}{9}

The ratio is \dfrac{I_1}{I_2}=\dfrac{4}{9}

8 0
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Steel Usually forms a
meriva

Answer:

Permanent magnetism (of the steel)

make me brainliestt :))

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3 years ago
What is the maximum number of electrons an oxygen atom can hold in its outer energy level?
gulaghasi [49]
The answer is 8. 
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3 years ago
According to Boyle’s Law, when pressure is increased...
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Boyle's law states that when you "shrink"(change its size) a container the pressure increases so the best answer would be D-volume is decreased.

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