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Ugo [173]
3 years ago
10

A number of conditions are required for a population to be in Hardy-Weinberg equilibrium. Which of the following are correct des

criptions of the conditions that must be met? Check all that apply.
A. no mutations

B. random mating

C. small population

D. migration or gene flow

E. occurrence of mutations

F. no natural selection
Physics
2 answers:
S_A_V [24]3 years ago
7 0

Answer: A, B, F

Explanation:

Marina CMI [18]3 years ago
3 0

There are total 5 number of conditions which are required in Hardy Weinberg Equilibrium to be established, of which no mutations, random mating and no natural selection, are given in the option.

Answer: A, B, F

<u>Explanation: </u>

To acquire the Hardy Weinberg equilibrium in the specified population, it must be kept in check for the random mating as given in the option. Other conditions are to have a large population which are free to mate and breed. Then there must be no allelic change in frequency as a result of mutation and mutation is allowed. The gene flow or the immigration of population or the emigration is not allowed. There must be no natural selection.  

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Zak, helping his mother rearrange the furniture in their living room, moves a 60 kg sofa 5.9 m with a constant force of 40 N. Wh
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Answer:236 J

Explanation:

Given

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Displacement s=5.9 m

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neglecting Friction

Work done is given by

W=F\cdot s

W=F\cdot s\cos 0

W=40\cdot 5.9

W=236 J

4 0
3 years ago
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What's the difference between mechanical waves and vibrations
OlgaM077 [116]

A mechanical wave is a wave that is an oscillation of matter, and therefore transfers energy through a medium. While waves can move over long distances, the movement of the medium of transmission—the material—is limited. Therefore, the oscillating material does not move far from its initial equilibrium position.

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3 years ago
A typical neutron star may have a mass equal to that of the Sun but a radius of only 20 km.(a) What is the gravitational acceler
Pepsi [2]

Answer:

331665750000\ m/s^2

3257806.62409 m/s

Explanation:

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u = Initial velocity = 0

v = Final velocity

s = Displacement = 16 m

a = Acceleration

Gravitational acceleration is given by

g=\dfrac{GM}{r^2}\\\Rightarrow g=\dfrac{6.67\times 10^{-11}\times 1.989\times 10^{30}}{20000^2}\\\Rightarrow g=331665750000\ m/s^2

The gravitational acceleration at the surface of such a star is 331665750000\ m/s^2

v^2-u^2=2as\\\Rightarrow v=\sqrt{2as+u^2}\\\Rightarrow v=\sqrt{2\times 331665750000\times 16+0^2}\\\Rightarrow v=3257806.62409\ m/s

The velocity of the object would be 3257806.62409 m/s

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As the temperature rises, the pressure must as well since pressure is the force the particles per unit of area exert on the container.

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Question 2 (10 points)
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Explanation:

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