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Keith_Richards [23]
3 years ago
6

A 1,400 kg car accelerates from rest to 30 m/s in 6.0 seconds. what is the net force on the car?

Physics
1 answer:
Allushta [10]3 years ago
4 0
So your finding acceleration first which is 30m/s divides by 6 seconds equals 5m/s^s and then multiply that by 1,400 kg and you have net force which is 7,000N
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Resistance is

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We can calculate the relationship between the area and the length to know in which direction the maximum currents

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Case 2

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        A = 0.15 0.43 = 0.0645 m2

        A / L = 0.248 m

Case 3

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        A / L = 0.0907 m

We can see that the case is the one  with the greatest current, L=15 cm

Let's calculate the current

     i = 5 / 1.7 10⁻⁸ (0.7453)

      i = 2.19 10⁸  A

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3 years ago
If the load on Pulley E is 20N, how much effort is needed to life it?
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It would need to be over 20 because if the load of the Pulley E is 20 and the effort is 20, then they will be equal and the Pulley would not move, so your answer is at least 20
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