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Keith_Richards [23]
3 years ago
6

A 1,400 kg car accelerates from rest to 30 m/s in 6.0 seconds. what is the net force on the car?

Physics
1 answer:
Allushta [10]3 years ago
4 0
So your finding acceleration first which is 30m/s divides by 6 seconds equals 5m/s^s and then multiply that by 1,400 kg and you have net force which is 7,000N
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Answer:

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Explanation:

<u>Motion With Constant Acceleration </u>

It occurs when an object changes its velocity at the same rate thus the acceleration is constant.

The relation between the initial and final speeds is:

v_f=v_o+at\qquad\qquad [1]

Where:

a   = acceleration

vo = initial speed

vf  = final speed

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\displaystyle x=v_o.t+\frac{a.t^2}{2}\qquad\qquad [2]

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\displaystyle a=\frac{v_f-v_o}{t}

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\displaystyle a=\frac{6.6-0}{6.5}

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The distance is now calculated with [2]:

\displaystyle x=0*6.5+\frac{1.015*6.5^2}{2}

x = 21.45 m

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Explanation:

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rjkz [21]

Answer:

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Explanation:

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3 years ago
Read 2 more answers
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