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8090 [49]
3 years ago
9

Where in the solar system (and beyond) have scientists found evidence of organic molecules?

Physics
1 answer:
mel-nik [20]3 years ago
7 0

Answer:

Beyond our solar system, organic molecules have been found in giant clouds of dust and gas between stars and in star-forming regions.

In our solar system, besides Earth, organic molecules have been discovered on comets, in meteorites, on Saturn's moon Titan, in the plumes of water expelled from Saturn's moon Enceladus, and on Neptune's moon Triton.

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Radius of Betelgeuse
MaRussiya [10]

820.9 million km thats your answer


7 0
4 years ago
In a ballistic pendulum an object of mass m is fired with an initial speed v0 at a pendulum bob. The bob has a mass M, which is
tresset_1 [31]

Answer:

The expression for the initial speed of the fired projectile is:

\displaystyle v_0=\frac{M+m}{m}(2gL[1-cos(\theta)]^{\frac{1}{2}})

And the initial speed ratio for the 9.0mm/44-caliber bullet is 1.773.

Explanation:

For the expression for the initial speed of the projectile, we can separate the problem in two phases. The first one is the moment before and after the impact. The second phase is the rising of the ballistic pendulum.

First Phase: Impact

In the process of the impact, the net external forces acting in the system bullet-pendulum are null. Therefore the linear momentum remains even (Conservation of linear momentum). This means:

P_0=P_f\\v_0m=v_i(m+M)\\v_0=v_i\frac{m+M}{m}  (1)

Second Phase: pendular movement

After the impact, there isn't any non-conservative force doing work in al the process. Therefore the mechanical energy remains constant (Conservation Of Mechanical Energy). Therefore:

Em_i=Em_f\\\frac{1}{2}mv^2_i=mgH\\v_i=[2gH]^\frac{1}{2}  (2)

The height of the pendulum respect L and θ is:

H=L(1-cos(\theta)) (3)

Using equations (1),(2) and (3):

\displaystyle v_0=\frac{M+m}{m}(2gL[1-cos(\theta)]^{\frac{1}{2}}) (4)

The initial speed ratio for the 9.0mm/44-caliber bullet is obtained using equation (4):

\displaystyle \frac{v_{9mm}}{v_{44}} =\frac{(M+m_{9mm})m_{44}}{(M+m_{44})m_{9}}(\frac{1-cos(\theta_{9mm})}{1-cos(\theta_{44})} )^{\frac{1}{2}}=1.773

3 0
3 years ago
List 2 examples of objects demonstrating mechanical energy.
OlgaM077 [116]
Windmills run on the principle of mechanical energy and work. Moving air (wind) possesses some amount of energy in the form of kinetic energy (due to motion). This energy gives the air the ability to do work on the blades of the fan.
6 0
2 years ago
The table shows information about four students who are running around a track. Which statement is supported by the information
murzikaleks [220]

Answer:

Mohammed has less kinetic energy than Autumn

Explanation:

The kinetic energy of each student is given by:

K=\frac{1}{2}mv^2

where

m is the mass of the student

v is the speed of the student

Let's use the formula above to calculate the kinetic energy of each student:

- Autumn: K=\frac{1}{2}(50 kg)(4 m/s)^2=400 J

- Mohammed: K=\frac{1}{2}(57 kg)(3 m/s)^2=256.5 J

- Lexy: K=\frac{1}{2}(53 kg)(3 m/s)^2=238.5 J

- Chiang: K=\frac{1}{2}(64 kg)(5 m/s)^2=800 J

Therefore, by looking at the numbers, we see that the correct answer is

Mohammed has less kinetic energy than Autumn

7 0
3 years ago
Read 2 more answers
The bulge of water on the side of earth closest to the moon produces _______.
Goryan [66]

That's a "high tide".

6 0
3 years ago
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