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vladimir2022 [97]
2 years ago
11

List 2 examples of objects demonstrating mechanical energy.

Physics
1 answer:
OlgaM077 [116]2 years ago
6 0
Windmills run on the principle of mechanical energy and work. Moving air (wind) possesses some amount of energy in the form of kinetic energy (due to motion). This energy gives the air the ability to do work on the blades of the fan.
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The engineer determines that the machine increased at a constant rate the disk’s angular speed from 100 rad/s to 300 rad/s over
aleksklad [387]

The disk's average angular speed during those 5 seconds was

(1/2) (100 + 300) rad/s = 200 rad/sec

Spinning for 5 sec at an average angular speed of 200 rad/s, the disk turned

(200 rad/s) x (5 s)  =  <em>1,000 radians</em>

(That's 500/pi revolutions = roughly 159.2 revolutions.)

5 0
3 years ago
What happens to the ball's velocity while the ball is traveling upwards?
Bess [88]
If the ball does not have a propeller or jet engine on it, then it is an object
in free fall.  That means its downward speed grows by 9.8 m/s for every
second that it's in the air. 

If it happens to be traveling upward at the moment, then that won't last long. 
Its upward speed is decreasing by 9.8 m/s every second.  It will eventually
run out of upward gas and start moving downward.  At that instant, you might
say that the direction of its velocity has changed by 180 degrees.
7 0
3 years ago
What determines the voltage of a light bulb?
valentinak56 [21]
The power source its getting usually determines its voltage.
5 0
3 years ago
Study the graph above. What can you conclude about ticket prices and concert attendance, based on this data?
iren2701 [21]

Answer:When the tickets prices went up the attendance went down because people wanted cheaper prices not higher prices.

Explanation:I hope i have helped u have an wonderful day or night!

7 0
2 years ago
A single loop of wire with an area of 0.0920 m2 is in a uniform magnetic field that has an initial value of 3.80 T, is perpendic
jekas [21]

Answer:

Induced emf in the loop is 0.02208 volt.

Induced current in the loop is 0.0368 A.

Explanation:

Given that,

Area of the single loop, A=0.092\ m^2

The initial value of uniform magnetic field, B = 3.8 T

The magnetic field is decreasing at a constant rate, \dfrac{dB}{dt}=0.24\ T/s

(a) The induced emf in the loop is given by the rate of change of magnetic flux.

\epsilon=\dfrac{-d\phi}{dt}\\\\\epsilon=A\times \dfrac{dB}{dt}\\\\\epsilon=0.092\times 0.24\\\\\epsilon=0.02208\ V

(b) Resistance of the loop is 0.6 ohms. Let I is the current induced in the loop. Using Ohm's law :

\epsilon=IR\\\\I=\dfrac{\epsilon}{R}\\\\I=\dfrac{0.02208}{0.6}\\\\I=0.0368\ A

Hence, this is the required solution.

5 0
3 years ago
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