Answer:
![\theta=82.87^0](https://tex.z-dn.net/?f=%5Ctheta%3D82.87%5E0)
u = 44.44 m/s
Explanation:
given,
horizontal displacement = 50 m
maximum height = 100 m
initial velocity (v₀) = ?
launching angle(θ) = ?
using formula
........(1)
.........(2)
dividing equation (2)/(1)
![\dfrac{h}{R} = \dfrac{\dfrac{u^2sin\theta}{2g}}{\dfrac{u^2sin2\theta}{g}}](https://tex.z-dn.net/?f=%5Cdfrac%7Bh%7D%7BR%7D%20%3D%20%5Cdfrac%7B%5Cdfrac%7Bu%5E2sin%5Ctheta%7D%7B2g%7D%7D%7B%5Cdfrac%7Bu%5E2sin2%5Ctheta%7D%7Bg%7D%7D)
![\dfrac{h}{R} =\dfrac{sin^2\theta}{2sin2\theta}](https://tex.z-dn.net/?f=%5Cdfrac%7Bh%7D%7BR%7D%20%3D%5Cdfrac%7Bsin%5E2%5Ctheta%7D%7B2sin2%5Ctheta%7D)
![\dfrac{4h}{R} =tan \theta](https://tex.z-dn.net/?f=%5Cdfrac%7B4h%7D%7BR%7D%20%3Dtan%20%5Ctheta)
![\theta= tan{-1}{\dfrac{4\times 100}{50}}](https://tex.z-dn.net/?f=%5Ctheta%3D%20tan%7B-1%7D%7B%5Cdfrac%7B4%5Ctimes%20100%7D%7B50%7D%7D)
![\theta=82.87^0](https://tex.z-dn.net/?f=%5Ctheta%3D82.87%5E0)
now using equation (2)
![100 = \dfrac{u^2sin82.87^0}{2\times 9.81}](https://tex.z-dn.net/?f=100%20%3D%20%5Cdfrac%7Bu%5E2sin82.87%5E0%7D%7B2%5Ctimes%209.81%7D)
u = 44.44 m/s
The ray will not emerge into the air medium from glass medium.
To find the answer, we need to know about the critical angle.
<h3>What's critical angle of glass?</h3>
- Critical angle of a medium can be determined from the relation as sinФ = 1/n, n = refractive index of that medium.
- As glass has refractive index of 1.5, so Critical angle = sin⁻¹(1/1.5) = 42 °
<h3>Why does the light incident at 45° inside a glass not emerge to the air medium?</h3>
- As we got the critical angle of glass is 42°, so the light incident at 45° which is greater than 42° will reflect back into the glass medium instead of emergence into the air medium.
Thus, we can conclude that the light will not emerge into air medium.
Learn more about the critical angle here:
brainly.com/question/15009181
#SPJ4
Answer:
Initial velocity, U = 28.73m/s
Explanation:
Given the following data;
Final velocity, V = 35m/s
Acceleration, a = 5m/s²
Distance, S = 40m
To find the initial velocity (U), we would use the third equation of motion.
V² = U² + 2aS
Where;
V represents the final velocity measured in meter per seconds.
U represents the initial velocity measured in meter per seconds.
a represents acceleration measured in meters per seconds square.
S represents the displacement measured in meters.
Substituting into the equation, we have;
35² = U + 2*5*40
1225 = U² + 400
U² = 1225 - 400
U² = 825
Taking the square root of both sides, we have;
Initial velocity, U = 28.73m/s