A increases plz dont report if wrong just tell me an ill fix it
Answer:
a = 8.951 m/s²
Explanation:
given,
angle = 0.52 radians
μ_s = 0.84
μ_k = 0.48
acceleration = ?
using
F + f = m a
mg sin θ + μk mg cos θ = m a
a = g sin θ + μk g cos θ
a = 9.8 x sin 0.52 + 0.48 x 9.8 x cos 0.52
a = 4.869 + 4.082
a = 8.951 m/s²
the magnitude of acceleration is a = 8.951 m/s²
Answer:
The work done by the force on the particle is 29.85 J.
Explanation:
The work is given by:
Where:
x₁: is the lower limit = 0 m
x₂: is the upper limit = 1.9 m
Fₓ: is the force in the horizontal direction = (4.5 + 13.7x - 1.5x²)N
Therefore, the work done by the force on the particle is 29.85 J.
I hope it helps you!
We do as follows:
energy = charge x voltage change .
Let q be the charge then E = q V
<span>and solving for q we have
q = E / V = -1.37e-5J / 2850V = -4.81x10-9 C
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Hope this answers the question. Have a nice day.
