Answer:
D. Debit Accounts Receivable $7,344; credit Interest Revenue $144; credit Notes Receivable $7,200.
Explanation:
Interest: $7,200 × .06 × 120/360 = $144
The entry that Majesty should record on the maturity date for this dishonored note is :
Debit Accounts Receivable $7,344
Credit Interest Revenue $144
Credit Notes Receivable $7,200.
Answer:
The answer is C and I am sure about that, so choose C
Answer:
which answers so i can help you mate
Explanation:
Answer:
Three levels of information systems at university include:
1. The students ICT unit (workgroup)
2. The departmental ICT units (enterprise)
3. The examination and records unit (inter enterprise)
Explanation:
The students ICT units and lab works together by communicating with one another in terms of file transfer, content chat systems and temporal record I keeping and processing.
The departmental information system operates at the higher level as an enterprise because at this stage the users at the work stations can no longer have full access to the platform because it is redefined to accommodate academic and non academic staff who are very useful in managing the data content, as well as keeping the security of these content intact against any form of security threats.
The examination and records unit on the final and higher level is the home server for all information systems security, backup and archive and the communication level regarded as the inter enterprise units. It is the final resort point when every other means of information and record keeping becomes threatened. Hence it is seen as the collation, record keeping and transfer point between one enterprise or department to the other.
Answer:
Vo = <u>C1 </u> + <u>C2 + V2</u>
1 + k (1 + K)2
Vo = <u>$129,600 </u> + <u>$129,600 + $3,200,000</u>
1 + 0.14 (1 + 0.14)2
Vo = $113,684.21 + $2,562,019.08
Vo = $2,675,703.29
The correct answer is C
Explanation:
The current value of the business equals cashflow in year 1 divided by 1 + K plus the aggregate of cashflow and sales value in year 2 divided by 1 + k raised to power 2.