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slega [8]
3 years ago
11

A nugget of GOLD has a mass 9.66 gram and a volume of 0.5 cm3, It's density isgrams/cm3 *​

Chemistry
1 answer:
dalvyx [7]3 years ago
4 0

Answer:

P=19.32g/cm³

Explanation:

m=9.66g

v=0.5cm³

P=mass/volume (density formula)

=9.66/0.5

=19.32g/cm³

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. An aqueous solution ‘A’ turns phenolphthalein solution pink. On addition of an aqueous solution ‘B’ to ‘A’, the pink colour di
lara31 [8.8K]

Answer:

(iii) A has pH greater than 7 and B has pH less than 7

Explanation:

Phenolphthalein is a common indicator in acid base titrations. It turns pink in basic conditions and turns colorless in acidic conditions. Thus on addition of solution A it becomes pink so A should be basic having pH more than 7. On addition of B , it turn out to be colorless means that B is an acidic solution having pH less than 7.

8 0
3 years ago
What type of sugar has the largest surface area
Valentin [98]

Answer:

d.) granulated

Because the granulated sugar has a greater surface area.

7 0
3 years ago
Write half reactions and the overall reaction occurred during discharging of acid lead battery.
Gre4nikov [31]
When  battery  discharge / delivering  current  the  lead  at  the  anode  is  oxidized
that  is ;
pb---->pb+  2e-
since  the  lead  ions  are  in  presence  of  aquous   sulfate  in  insoluble  lead  sulfate  precipitate onto the  electrode
the  overall   reaction  at  the  anode  is  therefore
Pb +  SO4^2-  ---> PbSO4  +  2e-
5 0
4 years ago
A solution of 100.0 mL of 0.200 M KOH is mixed with a solution of 200.0 mL of 0.150 M NiSO4. (a) Write the balanced chemical equ
NISA [10]

Answer:

a) 2KOH + NiSO₄ → K₂SO₄ + Ni(OH)₂

b) Ni(OH)₂

c) KOH

d) 0.927 g

e) K⁺=0.067 M, SO₄²⁻=0.1 M, Ni²⁺=0.067 M

Explanation:

a) The equation is:

2KOH + NiSO₄ → K₂SO₄ + Ni(OH)₂   (1)        

b) The precipitate formed is Ni(OH)₂  

 

c) The limiting reactant is:

n_{KOH} = V*M = 100.0 \cdot 10^{-3} L*0.200 mol/L = 0.020 moles

n_{NiSO_{4}} = V*M = 200.0 \cdot 10^{-3} L*0.150 mol/L = 0.030 moles

From equation (1) we have that 2 moles of KOH react with 1 mol of NiSO₄, so the number of moles of KOH is:

n = \frac{2}{1}*0.030 moles = 0.060 moles                  

Hence, the limiting reactant is KOH.  

d) The mass of the precipitate formed is:

n_{Ni(OH)_{2}} = \frac{1}{2}*n_{KOH} = \frac{1}{2}*0.020 moles = 0.010 moles

m = n*M = 0.010 moles*92.72 g/mol = 0.927 g  

e) The concentration of the SO₄²⁻, K⁺, and Ni²⁺ ions are:

C_{K^{+}} = \frac{2*\frac{1}{2}*n_{KOH}}{V} = \frac{0.020 moles}{0.300 L} = 0.067 M  

C_{SO_{4}^{2-}} = \frac{\frac{1}{2}*n_{KOH + (0.03 - 0.01)}}{V} = \frac{0.030 moles}{0.300 L} = 0.1 M

C_{Ni^{2+}} = \frac{0.020 moles}{0.300 L} = 0.067 M

I hope it helps you!                                                                        

5 0
4 years ago
Methanethiol, CH3SH, has a substantial dipole mement (1.52) even though carbon and sulfer have identical electronegativities. Ex
AleksAgata [21]

Answer:

The whole molecule is polar because Sulfur has lone pairs but Carbon doesn't. Lone pairs count more toward polarity, shifting dipole toward S.

Explanation:

Even though carbon and sulfur have identical values of electronegativities, the molecule, CH_3SH is polar because of the presence of the lone pairs on the sulfur atom.

The C-S bond is not polar because the both the atoms have electronegatiivty. <u>But S has lone pairs which can attract the bond pairs of the bond between the S and H and thus acquires slightly negative charge and H acquires slightly positive charge.</u>

6 0
3 years ago
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