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Salsk061 [2.6K]
3 years ago
8

Need help with this!!

Mathematics
1 answer:
Taya2010 [7]3 years ago
8 0

Answer:

The answer is B..... The corresponding is the identical number between all

The is 7 in each...

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12. The $60 selling price of a camera is the cost
lbvjy [14]

Answer:

I can help but your question does not make sense. You said the price of the camera is $60 and the question is find the cost?

Step-by-step explanation:

3 0
4 years ago
whe value of two rational number is 2,if one of the rational number is 1/7 so what is the value of other brainly
baherus [9]

Answer:

13/7

Step-by-step explanation:

X + 1/7 = 2

X = 2- 1/7

x = 13/7

6 0
3 years ago
Melissa and Tomas are playing a game with complex numbers. If Melissa has a score of 5-4i and Tomas has a score of 3+2i, what is
Gemiola [76]
8-2i is their total score.  You can't combine the imaginary numbers and real numbers.
3 0
3 years ago
Read 2 more answers
The object of the game is to toss a beanbag in the circular hole of a 48-by-24-inch board. If the diameter of the circle is 6 in
larisa [96]

Answer:

Geometric probability of an object hitting a circular hole is 0.0245.

Step-by-step explanation:

We have given,

A board of size 48 by 24 inch. There is a circular hole in the board having diameter 6 inches.

So,

Area of a board = 48 × 24 = 1152 square inches

And area of circular hole = π×r²   {where r = diameter/2  = 6 / 2 = 3 inches}

Area of circular hole = π×3² = 9π = 28.27 square inches

Now, we need to find the geometric probability of an object will hit the circle.

Geometric probability =  Area of circular hole / Area of board

Geometric probability = \frac{28.27}{1152}

Geometric probability = 0.0245

hence geometric probability of an object hitting a circular hole is 0.0245.

6 0
3 years ago
Which expression is equivalent to [(3xy^-5)^3/(x^-2y^2)^-4]^-2?
Mademuasel [1]

Answer:- a.The given expression is equivalent to  \frac{x^{10}y^{14}}{729}



Given expression:- [\frac{(3xy^{-5})^3}{(x^{-2}y^2)^{-4}}]^{-2}

=[\frac{(3)^3x^3y^{-5\times3}}{x^{-2\times-4}y^{2\times-4}}]^{-2}.........(a^m)^n=a^{mn}

=[\frac{27x^3y^{-15}}{x^8y^{-8}}]^{-2}

=[27x^{3-8}y^{-15-(-8)}]^{-2}............\frac{a^m}{a^n}=a^{m-n}

=[27x^{-5}y^{-7}]^{-2}=(27)^{-2}(x^{-5})^{-2}(y^{-7})^{-2}.........(a^m)^n=a^{mn}

=\frac{1}{(27)^2}(x^{10}y^{14})=\frac{x^{10}y^{14}}{729}

Thus a. is the right answer.


6 0
3 years ago
Read 2 more answers
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