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3 years ago

Which factor do 64x^2+48x+9 and 64x^2 - 9 have in common?

Mathematics

1 answer:

erastovalidia [21]3 years ago

8 0

(8x +3) (8x-3)
share the same terms

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If 6 cost $60, how much do 8 cost

madreJ [45]

Answer:

Step-by-step explanation:

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2 years ago

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Flora's Florist charges a standard delivery charge of

goldenfox [79]

Answer: $10.00 + 4.50r

r = rose

$10.00 = delivery charge

$4.50 = charge per rose

7 0

2 years ago

Find the total surface area of the triangular prism

GuDViN [60]

Answer:

$1,008\:\mathrm{cm^2}$

Step-by-step explanation:

The total surface area of this triangular prism consists of three rectangles and two triangles. Adding the areas of each of these shapes allows us to find the total surface area of this 3D figure:

Area of both triangles:

$2\cdot \frac{1}{2}\cdot12\cdot 14=168\:\mathrm{cm^2}$

Area of all three rectangles:

$15\cdot 20 +13\cdot 20+14\cdot 20=840\:\mathrm{cm^2}$

Therefore, the total surface area of this figure is:

$840+160=\fbox{$1,008\:\mathrm{cm^2}$} \: \checkmark$

3 0

2 years ago

Can someone please explain how to do this!!!

DedPeter [7]

Hi there!

So we are given that:-

tan theta = 7/24 and is on the third Quadrant.

In the third Quadrant or Quadrant III, sine and cosine both are negative, which makes tangent positive.

Since we want to find the value of cos theta. cos must be less than 0 or in negative.

To find cos theta, we can either use the trigonometric identity or Pythagorean Theorem. Here, I will demonstrate two ways to find cos.

Using the Identity

$\large \displaystyle{ {tan}^{2} \theta + 1 = {sec}^{2} \theta}$

Substitute tan theta = 7/24 in.

$\large \displaystyle{ {( \frac{7}{24}) }^{2} + 1 = {sec}^{2} \theta }$

Evaluate.

$\large \displaystyle{ \frac{49}{576} + 1 = {sec}^{2} \theta} \\ \large \displaystyle{ \frac{625}{576} = {sec}^{2} \theta}$

Reminder -:

$\large \displaystyle{ sec \theta = \frac{1}{cos \theta} }$

Hence,

$\large \displaystyle{ \frac{576}{625} = {cos}^{2} \theta} \\ \large \displaystyle{ \sqrt{ \frac{576}{625} } = cos \theta} \\ \large \displaystyle{ \frac{24}{25} = cos \theta}$

Because in QIII, cos<0. Hence,

$\large \displaystyle \boxed{ \blue{cos \theta = - \frac{24}{25} }}$

Using the Pythagorean Theorem

$\large \displaystyle{ {a}^{2} + {b}^{2} = {c}^{2} }$

Define c as our hypotenuse while a or b can be adjacent or opposite.

Because tan theta = opposite/adjacent. Therefore:-

$\large \displaystyle{ {7}^{2} + {24}^{2} = {c}^{2} } \\ \large \displaystyle{49 + 576 = {c}^{2} } \\ \large \displaystyle{625 = {c}^{2} } \\ \large \displaystyle{25 = c}$