All categories

3 years ago

if 42% of a crowd of 3850 at a football match were females, how many females attended the football game?

Mathematics

2 answers:

sweet [91]3 years ago

7 0

Answer: 1617

Step-by-step explanation:

You would need to find 42% of 3850

Convert 42% into decimal:

42/100 = 0.42

Multiply:

0.42*3850

= 1617

Therefore, there were 1617 females that attended the game

Sergio [31]3 years ago

5 0

Answer:

1617 females

Step-by-step explanation:

Step 1: Multiply 42 by 3850.

$42 * 3850$
$161700$

Step 2: Move the decimal place by 2 to the right.

$16170.0$
$1617.00$

Therefore, the answer is 1617 females.

Have a lovely rest of your day/night, and good luck with your assignments! ♡

You might be interested in

Which point is not on the graph of the equation y = x2 + 3x - 5. A.(2,5)

wel

Answer:C

Step-by-step explanation:

7 0

3 years ago

John and O’Neill are playing a boardgame in which they roll to number cubes. John needs to get some of a on the number cubes to

Pani-rosa [81]

Answer: John is most likely to win.

Step-by-step explanation: John is most likely to win because he can roll the following numbers:

2,6

3,5

4,4

5,3

6,2

Oh Neil Can only roll these numbers

5,6

6,5

So John would most Likely win

6 0

3 years ago

A 5-meter ladder is leaning against the side of a house. The foot of the ladder is pulled away from the house at a rate of 0.4 m

Flura [38]

<h2>The top of the ladder is descending at 0.3 m/s.</h2>

Step-by-step explanation:

By Pythagoras theorem we know that

Hypotenuse² = Base² + Perpendicular²

h² = b² + p²

We have for ladder

h = 5 m

b = 3 m

5² = 3² + p²

p = 4 m

$\frac{db}{dt}=0.4m/s\\\\\frac{dh}{dt}=0$

Differentiating h² = b² + p² with respect to time

$2h\times \frac{dh}{dt}=2b\times \frac{db}{dt}+2p\times \frac{dp}{dt}\\\\5\times 0=3\times 0.4+4\times \frac{dp}{dt}\\\\\frac{dp}{dt}=-0.3m/s$

The top of the ladder is descending at 0.3 m/s.

3 0

3 years ago

Help ASAp peaseeeeeeeeee

PIT_PIT [208]

Answer:

7/6

Step-by-step explanation:

$\frac{ \frac{x}{4} + \frac{x}{3} }{ \frac{x}{2} } = \frac{x( \frac{1}{4} + \frac{1}{3} )}{ x(\frac{1}{2}) } \\ = \frac{ \frac{1}{4} + \frac{1}{3} }{ \frac{1}{2} } \\ = \frac{14}{12} = \frac{7}{6}$

3 0

2 years ago

Read 2 more answers

The fictional rocket ship Adventure is measured to be 65 m long by the ship's captain inside the rocket.When the rocket moves pa

Gwar [14]

Answer:

a) t₀ = 1.73205 s

b) 1.0 C

Step-by-step explanation:

(A)

The time dilation (t) observed by an observer at rest relative to the time (t₀) measured by observer in motion is;

$t = \frac{t_0}{\sqrt{1 - \frac{V^2}{C^2}}}$

$t_0 = t \sqrt{1 - \frac{V^2}{C^2}}$ time measured by captain

⇒ $t_0 = 2.0 \sqrt{1 - \frac{0.5^2C^2}{C^2}}$ V = 0.5 c

⇒ t₀ = 1.73205 s

(B)

Speed of the light never exceeds by its real value. The speed of the light in any frame of reference is constant.

∵ It will be "1.0C" or just "C"

7 0

3 years ago