This equation uses y and x so it cannot be factorised.
Let’s try the equation y^2 - 12y + 36 = 0
Look for two factors of 36 that add to -12.
This would be -6 and -6
(y - 6)(y - 6) = 0
(y - 6) must equal 0
y = 6
<span>1.Write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (2,-2);y=-x-2
D.y=-x
2.Write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (2,-1);y=-3/2x-6
C.y=-3/2x+2
3.Write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (4,2);x=-3
D.y=4
4.Write an equation in slope- intercept form of the line that passes through the given point and is perpendicular to the graph of the given equation. (-2,3);y=1/2x-1
B.y=-2x-1
5.Write an equation in slope- intercept form of the line that passes through the given point and is perpendicular to the graph of the given equation. (5,0);y+1=2(x-3)
D.y=-1/2x+5/2</span>
Solution
-3b + 11 = -18 + 8b
-3b - 8b = -18 - 11
-11b = -29
b = 29/11
Answer:
The value to the given expression is 8
Therefore ![\left[\frac{(10^4)(5^2)}{(10^3)(5^3)}\right]^3=8](https://tex.z-dn.net/?f=%5Cleft%5B%5Cfrac%7B%2810%5E4%29%285%5E2%29%7D%7B%2810%5E3%29%285%5E3%29%7D%5Cright%5D%5E3%3D8)
Step-by-step explanation:
Given expression is (StartFraction (10 Superscript 4 Baseline) (5 squared) Over (10 cubed) (5 cubed)) cubed
Given expression can be written as below
![\left[\frac{(10^4)(5^2)}{(10^3)(5^3)}\right]^3](https://tex.z-dn.net/?f=%5Cleft%5B%5Cfrac%7B%2810%5E4%29%285%5E2%29%7D%7B%2810%5E3%29%285%5E3%29%7D%5Cright%5D%5E3)
To find the value of the given expression:
![\left[\frac{(10^4)(5^2)}{(10^3)(5^3)}\right]^3=\frac{((10^4)(5^2))^3}{((10^3)(5^3))^3}](https://tex.z-dn.net/?f=%5Cleft%5B%5Cfrac%7B%2810%5E4%29%285%5E2%29%7D%7B%2810%5E3%29%285%5E3%29%7D%5Cright%5D%5E3%3D%5Cfrac%7B%28%2810%5E4%29%285%5E2%29%29%5E3%7D%7B%28%2810%5E3%29%285%5E3%29%29%5E3%7D)
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Therefore ![\left[\frac{(10^4)(5^2)}{(10^3)(5^3)}\right]^3=8](https://tex.z-dn.net/?f=%5Cleft%5B%5Cfrac%7B%2810%5E4%29%285%5E2%29%7D%7B%2810%5E3%29%285%5E3%29%7D%5Cright%5D%5E3%3D8)
Therefore the value to the given expression is 8
Given:
Speed = 6 miles per second
If the Saturn revolves 6 miles in 1 second then the speed is:

So speed in minutes is 360 miles per min.
In 3 minutes traveling distance is: