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wolverine [178]
3 years ago
14

-Help with math homework chapter 1 practice -Show work for the questions

Mathematics
2 answers:
bezimeni [28]3 years ago
4 0

Answer:

23

Step-by-step explanation:

because when you do 24-1 it is 23

frosja888 [35]3 years ago
3 0
I think The answer is 23.
You might be interested in
The price of a dress is reduced by 55​0%. When the dress still does not​ sell, it is reduced by 55​0% of the reduced price. If t
Masja [62]

Answer:

x = $200

The original price is $200

Question :

The price of a dress is reduced by 50%. When the dress still does not​ sell, it is reduced by 50% of the reduced price. If the price of the dress after both reductions is ​$50, what was the original​ price?

Step-by-step explanation:

Let x represent the original price of the dress.

First reduction

After first reduction the value of the price is given as;

p1 = x - 50% of x = (1-0.50)x = 0.5x

p1 = 0.5x

Second reduction

After the second reduction the value of the price is given as;

p2 = p1 - 50% of p1 = (1-0.50)p1 = (0.50)0.50x

p2 = 0.25x .....1

Since, p2 is given

p2 = $50

Substituting into equation 1

$50 = 0.25x

x = $50/0.25 = $200

x = $200

The original price is $200

4 0
3 years ago
In a certain year, the price of gasoline rose by 20% during January, fell by 20% during February, rose by 25% in March, and fell
satela [25.4K]

Using decimal multipliers, it is found that the value of x is of 16.67.

<h3>What is a decimal multiplier?</h3>

Increases of a% or decreases of a% re represented by decimal values, as follows:

  • The equivalent multiplier for an increase of a% is given by: \frac{100 + a}{100}
  • The equivalent multiplier for an decrease of a% is given by: \frac{100 - a}{100}

In this problem:

  • The price at the beginning of January was of a.
  • Increase of 20% in January, hence 1.2a.
  • Decrease of 20% in February, hence 1.2(0.8)a.
  • Increase of 25% in March, hence 1.2(0.8)(1.25)a.
  • Decrease of x% in April, hence 1.2(0.8)(1.25)\left(\frac{100 - x}{100}\right)a

The price of gasoline at the end of April was the same as it had been at the beginning of January, hence:

a =1.2(0.8)(1.25)\left(\frac{100 - x}{100}\right)a

1.2\left(\frac{100 - x}{100}\right) = 1

\left(\frac{100 - x}{100}\right) = \frac{1}{1.2}

\frac{100 - x}{100} = 0.8333

100 - x = 83.33

x = 16.67

The value of x is of 16.67.

To learn more about decimal multipliers, you can take a look at brainly.com/question/24952336

6 0
2 years ago
Hey! Can someone help me?
bazaltina [42]

Answer:

I believe the answer is B

5 0
3 years ago
Sally buys a hang bag. There was a discaount of 35percent . If Sally paid $56.80 what was the original price?
Ksju [112]
Discount = 35%
Percentage after discount = 100% - 35% = 65%

65% = $56.80
1% = $0.8738
100% = $87.38

Answer: The original price is $87.38
4 0
3 years ago
Read 2 more answers
Use the rules of significant figures to answer the following question: 22.674 • 15.05
olga_2 [115]
I think it is b. 341.24
6 0
3 years ago
Read 2 more answers
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