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3 years ago

Which of the following elements would most likely become a positive ion when forming a chemical bond?

1 answer:

4 0

Here, Your Options are absent, but the elements that would most likely become a positive ion will be:

hydrogen, sodium, potassium, lithium, cesium etc.

Hope this helps!

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I Need Assistance With This Equation:

nikklg [1K]

Check the picture below.

now, for 6 triangles, well, simply 6*6.

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4 years ago

An organism tissues and organ are made or cells. T or F

marta [7]

The answer is true
Hope it helped

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3 years ago

Two football players with mass 75kg and 100kg run directly toward each other with speeds of 6 m/s and 8 m/s respectively, If the

Rina8888 [55]

Answer:

2 m/s

Explanation:

From the law of conservation of momentum,

Total momentum before collision = total momentum after collision

mu+m'u' = V(m+m') .................................Equation 1

Where m = mass of the first player, u = initial speed of the first player, m' = mass of the second player, u' = initial speed of the second player, V = combined speed of both players.

Making V the subject of the equation,

V = (mu+m'u')/(m+m')................ Equation 2

Note: Taking the direction of the first player as positive.

Given: m = 75 kg, m' = 100 kg, u = 6 m/s, u' = -8 m/s (opposite the first player),

Substituting into equation 2

V = [(75×6)+(100×(--8))]/(75+100)

V = (450-800)/175

V = 350/175

V = - 2 m/s.

Note: The negative signs tells that the combined speed is in the direction of the second player.

Hence the combined speed of the two players = 2 m/s

8 0

4 years ago

Two 1.1 kg masses are 1 m apart (center to center) on a frictionless table. Each has +10 JC of charge. What is the initial accel

sweet-ann [11.9K]

Answer:

acceleration = 0.8181 m/s²

Explanation:

given data

mass = 1.1 kg

apart d = 1 m

charge q = 10 μC

to find out

What is the initial acceleration

solution

we know that acceleration is

acceleration = $\frac{force}{mass}$ .................1

here force = $k \frac{q1q2}{r^2}$

here q1 q2 is charge and r is distance and Coulomb constant k = 9 × $10^{9}$ Nm²/C²

force = $9*10^{9} \frac{(10*10^{-6})^2}{1^2}$

force = 0.9 N

so from equation 1

acceleration = $\frac{0.9}{1.1}$

acceleration = 0.8181 m/s²

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3 years ago

evablogger [386]

The answer is a bc electric is fast

7 0

4 years ago

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