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inn [45]
4 years ago
13

What can we say about a polarizing filter with vertically aligned chemical molecules?

Physics
1 answer:
klemol [59]4 years ago
3 0

Answer:

A . It will allow vertically polarized light to pass through it.

Explanation:

Polarization is the attribute in which waves oscillate in a particular direction relative to the direction of travel. The direction of polarization determines the type of polarized light produced. Since the chemical molecules are vertically aligned, it will only allow vertically polarized light pass through it.

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How much power will be required to force a current of 4.13 amps to flow through a conductor whose resistance is 113 ohms? Use tw
-Dominant- [34]

The power required to force the current of 4.13 A to flow through the conductor is 1927.43 watts

<h3>What is power? </h3>

This is defined as the rate in which energy is consumed. Electrical power is expressed mathematically as:

Power (P) = square current (I²)× resistancet (R)

P = I²R

<h3>How to determine the power</h3>
  • Current (I) = 4.13 A
  • Resistance (R) = 113 ohms
  • Power (P) =?

P = I²R

P = 4.13² × 113

P = 1927.43 watts

Thus, the power required is 1927.43 watts

Learn more about electrical power:

brainly.com/question/64224

#SPJ1

7 0
2 years ago
write an essay about "the importance of knowing the fluids" / the importance of fluid knowledge dunno exactly. Plz help
Gala2k [10]
DRINK ALOT  of fluid is the anwser
6 0
3 years ago
What is the science behind the making of pop-up books?
IRINA_888 [86]

Answer

The moveable parts of the pop up book are of often cut out by hand and are folded and glued by hand upon the printed pages. The cover is glued or sewn to the lining. Front and backs are often made up from board, which is just a heavier gauge paper than is used for the pages.

Explanation

Hope that this helps you and have a great day:)

6 0
3 years ago
Two thin concentric spherical shells of radii r1 and r2 (r1 &lt; r2) contain uniform surface charge densities V1 and V2, respect
Lyrx [107]

Answer:

Answer is explained in the explanation section below.

Explanation:

Solution:

We know that the Electric field inside the thin hollow shell is zero, if there is no charge inside it.

So,

a)  0 < r < r1 :

We know that the Electric field inside the thin hollow shell is zero, if there is no charge inside it.

Hence, E = 0 for r < r1

b)  r1 < r < r2:

Electric field =?

Let, us consider the Gaussian Surface,

E x 4 \pi r^{2}  = \frac{Q1}{E_{0} }

So,

Rearranging the above equation to get Electric field, we will get:

E = \frac{Q1}{E_{0} . 4 \pi. r^{2}   }

Multiply and divide by r1^{2}

E = \frac{Q1}{E_{0} . 4 \pi. r^{2}   } x \frac{r1^{2} }{r1^{2} }

Rearranging the above equation, we will get Electric Field for r1 < r < r2:

E= (σ1 x r1^{2}) /(E_{0} x r^{2})

c) r > r2 :

Electric Field = ?

E x 4 \pi r^{2}  = \frac{Q1 + Q2}{E_{0} }

Rearranging the above equation for E:

E = \frac{Q1+Q2}{E_{0} . 4 \pi. r^{2}   }

E = \frac{Q1}{E_{0} . 4 \pi. r^{2}   } + \frac{Q2}{E_{0} . 4 \pi. r^{2}   }

As we know from above, that:

\frac{Q1}{E_{0} . 4 \pi. r^{2}   } =  (σ1 x r1^{2}) /(E_{0} x r^{2})

Then, Similarly,

\frac{Q2}{E_{0} . 4 \pi. r^{2}   } = (σ2 x r2^{2}) /(E_{0} x r^{2})

So,

E = \frac{Q1}{E_{0} . 4 \pi. r^{2}   } + \frac{Q2}{E_{0} . 4 \pi. r^{2}   }

Replacing the above equations to get E:

E = (σ1 x r1^{2}) /(E_{0} x r^{2}) + (σ2 x r2^{2}) /(E_{0} x r^{2})

Now, for

d) Under what conditions,  E = 0, for r > r2?

For r > r2, E =0 if

σ1 x r1^{2} = - σ2 x r2^{2}

4 0
3 years ago
Newer aircraft jet catapult systems use magnets instead of steam. The launch still takes 1.19 seconds, but the acceleration is a
Westkost [7]

Answer:

33.6 m

Explanation:

Given:

v₀ = 0 m/s

a = 47.41 m/s²

t = 1.19 s

Find: Δx

Δx = v₀ t + ½ at²

Δx = (0 m/s) (1.19 s) + ½ (47.41 m/s²) (1.19 s)²

Δx = 33.6 m

8 0
3 years ago
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