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Contact [7]
3 years ago
14

Calculate the location xcm of the center of mass of the Earth-Moon system. Use a coordinate system in which the center of the Ea

rth is at x=0 and the Moon is located in the positive x direction.
Physics
1 answer:
Serga [27]3 years ago
7 0

Answer:

4.6\times 10^3 km

Explanation:

We are given that

Mass of Earth,M=6\times 10^{24} kg

Mass of moon,m=7.35\times 10^{22} kg

x_1=0

Distance between Earth and moon,x_2=3.80\times 10^5 km

We have to find the location of the center of mass of the Earth- Moon system.

Position of center of mass of Earth-Moon system

x=\frac{Mx_1+mx_2}{m+M}

Using the formula

x=\frac{6\times 10^{24}\times 0+7.35\times 10^{22}\times 3.8\times 10^5}{6\times 10^{24}+7.35\times 10^{22}}

x=4.599\times 10^3 Km\approx 4.6\times 10^3 km

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a nitrogen laser generates a pulse containing 10.0 mj of energy at a wavelength of 340.0 nm. how many photons are in the pulse?
Wewaii [24]

A nitrogen laser generates a pulse containing 10.0 mj of energy at a wavelength of 340.0 nm and has 1785 x 10¹⁹ photons in the pulse.

<h3>How many photons are in the pulse?</h3>

Energy of a single photon is

E=hcλ

E=6.626×10⁻³⁴ J s×3×108 m/s /340×10⁻⁹ m

E=6.31×10⁻¹⁹  J

Number of photons in the laser is

n=Total Energy/Energy per photon

n=10⁷×10⁻³J /5.90×10⁻¹⁹J/photon

n= 1785 x 10¹⁹ photons

To learn about photons, refer: brainly.com/question/20912241?referrer=searchResults

#SPJ4

6 0
2 years ago
Find the equivalent resistance of this
MAXImum [283]

Explanation:

1/R = 1/R1 + 1/ R2

1/R = 1/960 + 1/640

1/R = 5 / 1920

<h3> R = 384 ohm </h3>

So , Req = 384 + R3

Req = 384 + 180

<h3> Req = 564 ohm</h3>

\huge\red{A}\pink{N}\orange{S}{W}\blue{E}\green{R}

<h2> Req = 564 ohm</h2>

7 0
2 years ago
What magnitude charge creates a 32.08 N/C electric field at a point 2.84 m away?
sammy [17]

Answer:

Q = 29.4 x 10⁻⁹ C.

Explanation:

Electric field due to a charge Q at distance d is given by coulomb law as follows

Electric field

E = k Q /d²

where for air k which is a constant is 9 x 10⁹

E=\frac{k\times Q}{d^2}

Given E = 32.08 , d = 2.84 m

Putting these values in the relation above, we have

[tex]32.08=\frac{9\times 10^9\times Q}{(2.84)^2}[/tex]

Q = 29.4 x 10⁻⁹ C.

5 0
3 years ago
How do you add scientific notation if the problem is like this:<br>3.72 x 10^9  +  5.46 x 10^8?
Crazy boy [7]
You can only add or subtract numbers in scientific notation if they have
the same power of 10.  If they're different, then you have to change one
to match the other one.

Here are both ways to do your example:

3.72x 10^9 = 37.2x10^8

(37.2 x 10^8)+(5.46 x 10^8) = (37.2+5.46) x 10^8 = 42.66x10^8 = <em>4.266x10^9</em>

=======================

5.46 x 10^8 = 0.546 x 10^9

3.72 x 10^9 + 0.546 x 10^9 = (3.72 + 0.546) x 10^9 = <em>4.266 x 10^9</em>
3 0
4 years ago
Much of the general structure and physical properties of the interior of the earth are inferred from:
katovenus [111]

I'm 100% sure its C hope this helps


3 0
3 years ago
Read 2 more answers
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