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Alex73 [517]
3 years ago
8

Can x-2 ever be less than 0? Why or why not?

Mathematics
2 answers:
nekit [7.7K]3 years ago
5 0
Of course it can.  It always is if 'x' is less than 2.
EastWind [94]3 years ago
4 0
Yes, it can.

See inequality:

x-2 < 0
x < 2

So, any value of x smaller than 2 become x- 2 a negative result.


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Your current schedule only lets you take two 1-credit courses every six months. You need 12 credits to get the degree you want.
lianna [129]
So,

Since you can only take two one-credit courses every six months, you can earn 2 credits every six months, and 4 credits in one year.  Multiplying that by 3, you get 12 credits in 3 years.

It will take 3 years to get the degree.
6 0
3 years ago
Compare -3.6 and 1.2.
jasenka [17]

Answer:

-3.6 is a negative number compared to 1.2. 1.2 is -3 times less than -3.6. -3.6 is -3 times more than 1.2

Step-by-step explanation:

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8 0
3 years ago
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If 5 is subtracted from the square of a number ,the result is 4 , find the number.
Levart [38]

Answer:

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Step-by-step explanation:

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7 0
3 years ago
For each sequence write an explicit formula 96,48,24,12,6
STALIN [3.7K]
a_1=96;\ a_2=48;\ a_3=24;\ a_4=12;\ a_5=6\\\\a_1=a_2:2\to96:2=48\\a_2=a_3:2\to48:2=24\\a_3=a_2:2\to24:2=12\\a_4=a_3:2\to12:2=6\\\\therefore\\\\a_n=96:2^{n-1}=\frac {96}{2^{n-1}}\\\\check:\\a_1=\frac{96}{2^{1-1}}=\frac{96}{1^0}=96\\a_2=\frac{96}{2^{2-1}}=\frac{96}{2^1}=\frac{96}{2}=48\\a_3=\frac{96}{2^{3-1}}=\frac{96}{2^2}=\frac{96}{4}=24\\\vdots
8 0
3 years ago
Jonathan goes to the store and purchases 3 pencils for 0.28 each, and y number of erasers for 0.38 each. Write an expression tha
laiz [17]

Keywords


linear equation, variables


Step 1


Define the variables


Let


x-----> number of erasers


y-----> total cost


we know that




 ------> this is the linear equation that represent the situation


therefore


the answer is y = 0.84 + (0.38)x



5 0
3 years ago
Read 2 more answers
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