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3 years ago

Can x-2 ever be less than 0? Why or why not?

Mathematics

2 answers:

nekit [7.7K]3 years ago

5 0

Of course it can. It always is if 'x' is less than 2.

EastWind [94]3 years ago

4 0

Yes, it can.

See inequality:

x-2 < 0
x < 2

So, any value of x smaller than 2 become x- 2 a negative result.

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Step-by-step explanation:

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3 years ago

Please help !! I would really appreciate it

Savatey [412]

Answer:

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Step-by-step explanation:

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3 years ago

In which step did Viet make an error? 2 ( x − 3 ) 2 + 4 = 102 2 ( x − 3 ) 2 = 106 Step 1 ( x − 3 ) 2 = 53 Step 2 x − 3 = ± 53 St

vitfil [10]

Answer:

Step 2

Step-by-step explanation:

Given

Step 1: $2(x - 3)^2 + 4 = 102$

Step 2: $2(x - 3)^2 = 106$

Step 3: $x - 3 = \±\sqrt{53$

Step 4: $x = \±\sqrt{53} + 3$

Required

Where did Viet made an error?

The step 1 indicates the original question.

$2(x - 3)^2 + 4 = 102$

To get to step 2, we have to subtract 4 from both sides of the equation.

$2(x - 3)^2 + 4 -4= 102 - 4$

$2(x - 3)^2 = 98$

However, the above expression is different from Viet's evaluation.

<em>Hence, we can conclude that Viet made an error in step 2</em>

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3 years ago